排除日志中的grep文件名

Question

I have a problem with my bash script. I want to excluding from processing files that are listed in the exclude.log. After a file is processed it is written in to the exclude log.

for I in `ls $1 | grep ./exclude.log -v`

do
    echo "Procesing ...."
    echo $I >> ./exclude.log
done

Answer 1

You can use this while loop:

while read -r l; do
   echo "$l"; 
done < <(fgrep -v -wf exclude.log <(printf "%s\n" "$1"/*))

Answer 2

$I is not assigned a value. Also your grep is not right formulated.

You possibly want

LIST=$( grep -v -f /path/to/exclude.log * )
for I in $LIST
do
        echo "Procesing ...."
        echo $I >> /path/to/exclude.log
done

Make sure you don't have any empty lines in exclude.log