java.util.MissingResourceException：找不到基本名称'property_file name'的捆绑包，语言环境en_US

Question

I am trying to create a utility class ReadPropertyUtil.java for reading data from property file. While my class is located under a util directory, my skyscrapper.properties file is placed in some other directory.

But, when i try to access the properties using [ResourceBundle][1] , i get exceptions, that bundle can't be loaded.

Below is the code on how I am reading the properties and also an image which shows my directory structure.

ReadPropertiesUtil.java

/**
 * Properties file name.
 */
private static final String FILENAME = "skyscrapper";

/**
 * Resource bundle.
 */
private static ResourceBundle resourceBundle = ResourceBundle.getBundle(FILENAME);

/**
 * Method to read the property value.
 * 
 * @param key
 * @return
 */
public static String getProperty(final String key) {
    String str = null;
    if (resourceBundle != null) {
        str = resourceBundle.getString(key);
            LOGGER.debug("Value found: " + str + " for key: " + key);
    } else {
            LOGGER.debug("Properties file was not loaded correctly!!");
    }
    return str;
}

Directory Structure

This line is giving the error private static ResourceBundle resourceBundle = ResourceBundle.getBundle(FILENAME);

I am unable to understand why isn't this working and what is the solution. The src folder is already added in build path completely.

Answer 1

尝试使用资源的完全限定名称：

private static final String FILENAME = "resources/skyscrapper";

Answer 2

ResourceBundle doesn't load files? You need to get the files into a resource first. How about just loading into a FileInputStream then a PropertyResourceBundle

   FileInputStream fis = new FileInputStream("skyscrapper.properties");
   resourceBundle = new PropertyResourceBundle(fis);

Or if you need the locale specific code, something like this should work

File file = new File("skyscrapper.properties");
URL[] urls = {file.toURI().toURL()};
ClassLoader loader = new URLClassLoader(urls);
ResourceBundle rb = ResourceBundle.getBundle("skyscrapper", Locale.getDefault(), loader);

Answer 3

Use the Resource like

ResourceBundle rb = ResourceBundle.getBundle("com//sudeep//internationalization//MyApp",locale);
or
ResourceBundle rb = ResourceBundle.getBundle("com.sudeep.internationalization.MyApp",locale);

Just give the qualified path .. Its working for me!!!

Answer 4

您应该设置不带.properties扩展名的属性文件名，它对我来说可以正常工作:)

Answer 5

I'd like to share my experience of using Ant in building projects, *.properties files should be copied explicitly . This is because Ant will not compile *.properties files into the build working directory by default (javac just ignore *.properties). For example:

<target name="compile" depends="init">
    <javac destdir="${dst}" srcdir="${src}" debug="on" encoding="utf-8" includeantruntime="false">
        <include name="com/example/**" />
        <classpath refid="libs" />
    </javac>
    <copy todir="${dst}">
        <fileset dir="${src}" includes="**/*.properties" />
    </copy>
</target>

<target name="jars" depends="compile">
    <jar jarfile="${app_jar}" basedir="${dst}" includes="com/example/**/*.*" />
</target>

Please notice that 'copy' section under the 'compile' target, it will replicate *.properties files into the build working directory. Without the 'copy' section the jar file will not contain the properties files, then you may encounter the java.util.MissingResourceException.

Answer 6

The simplest code would be like, keep your properties files into resources folder, either in src/main/resource or in src/test/resource. Then use below code to read properties files:

public class Utilities {
    static {
        rb1 = ResourceBundle.getBundle("fileNameWithoutExtension"); 
              // do not use .properties extension
    }
    public static String getConfigProperties(String keyString) {
        return rb1.getString(keyString);
    }
}

Answer 7

With Eclipse and Windows:

you have to copy 2 files - xxxPROJECTxxx.properties - log4j.properties here : C:\Eclipse\CONTENER\TOMCAT\apache-tomcat-7\lib

Answer 8

I have just realized that my error was caused in the naming convention of my property file. When i used xxxx.xxxx.properties i got the error:

java.util.MissingResourceException: Can't find bundle for base name 'property_file name', locale en_US

Changing it to something like xxx-xxxx.properties works like a charm. Hope i help someone!

Answer 9

只需右键单击 Eclipse 中的项目文件并在构建路径中选择“用作源文件夹”...它对我有用

Answer 10

You can try anyone with resources-

private static final String FILENAME = "resources.skyscrapper";
private static final String FILENAME = "resources/skyscrapper";
private static final String FILENAME = "resources\\skyscrapper";
private static final String FILENAME = "resources//skyscrapper";

By default it tries to find 'skyscrapper.properties' file inside 'src' but you have placed your file inside a sub-directory 'resources' which is unreachable.

In a maven project-

It looks like- 'src/main/resources/skyscrapper.properties' then use-

private static final String FILENAME = "skyscrapper";

And if it looks like- 'src/main/resources/prop/xyz/skyscrapper.properties' then use-

private static final String FILENAME = "prop/xyz/skyscrapper";
private static final String FILENAME = "prop.xyz.skyscrapper";

In this case by default it tries to find 'skyscrapper.properties' file inside 'src/main/resources' but your file is actually inside a subdirectory of resources then you need to provide relative path otherwise you may receive exception like-

Exception in thread "main" java.util.MissingResourceException: Can't find bundle for base name src\main\resources\prop\xyz\skyscrapper.

Answer 11

Check project build path. May be only the *.java files are included. This problem occured in my Maven project. I needed to alter my pom.xml file.

<build>
        <resources>
            <resource>
                <directory>src/main/java</directory>
                <filtering>true</filtering>
                <includes>
                    <include>**/*.properties</include>
                </includes>
            </resource>
        </resources>
</build>

Answer 12

if you are using maven try this:

public static Connection getConnection(){
    //*******************************************************************
    try(InputStream input = new FileInputStream("path to file")){
        Properties prop = new Properties();
        prop.load(input);
        String driver = prop.getProperty("driver");
        String url = prop.getProperty("url");
        String user = prop.getProperty("user");
        String password = prop.getProperty("password");
        //Class.forName(driver);
        connection = DriverManager.getConnection(url, user, password);
    } catch (Exception e) {
        e.printStackTrace();

    }

    return connection;