如何从实现该接口的类的对象（自动）为接口创建模拟对象？

Question

well I have an interface called InputInterface, which has some get methods. I also have a complex gui class, which implements that InputInterface, now since it's too complicated to serialize that whole class and it extends and implements more interfaces, I'd like to create something like a mock object, which would create something like a copy of the answers that my complex class gives out at the current moment.

I wanted to create a class implementing that interface, which would hold the values, but then I realized this should be a standard procedure for things like EasyMock or other mocking libs? Just how can this be done?

Thanks in advance.

Answer 1

You can actually instantiate an interface, specifying the required methods.

MyInterface myInterface = new MyInterface() {
    public void requiredMethod(...) {
        //...
    }
};

Answer 2

Mockito provides a "spy" mechanism to wrap an existing object and thereby be able to observe method calls and potentially stub individual method calls. However, it does not provide a mechanism to cache the first call to the spied object and then continuously return this value.

Mockito - see the section of "Spy of real object"

I found this via a google search of "Mockito spy cache". It seems like it might do the trick.

Mockito caching-spy