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根据复选框隐藏/显示表格行

[英]Hide/Show table row(s) based on checkbox

I have a dynamic list of dates. 我有一个动态的日期列表。 I want to create a checkbox for each unique date, and then list all dates in a table row format below. 我想为每个唯一日期创建一个复选框,然后以下面的表格格式列出所有日期。 The goal is when a checkbox is checked/unchecked, any rows with a class the same as the checkbox value will hide/show. 目标是当选中/取消选中复选框时,任何类与复选框值相同的行都将隐藏/显示。

Any help is appreciated. 任何帮助表示赞赏。

$('input[type = checkbox]').change(function () {
    var self = this;
    $(self).closest('table').find('tbody tr').filter('.' + self.value).toggle(self.checked);
});





<div class="widget">
    <div class="rowElem noborder">
        <div class="formRight">
            <label>
                <input type="checkbox" class="show" value="2013-11-15" checked />2013-11-15</label>
        </div>
        <div class="formRight">
            <label>
                <input type="checkbox" class="show" value="2013-11-17" checked />2013-11-17</label>
        </div>
        <div class="formRight">
            <label>
                <input type="checkbox" class="show" value="2013-11-20" checked /> 2013-11-20</label>
        </div>
    </div>
</div>
<table>
    <tbody>
        <tr class="2013-11-15">
            <td>2013-11-15</td>
        </tr>
        <tr class="2013-11-15">
            <td>2013-11-15</td>
        </tr>
        <tr class="2013-11-20">
            <td>2013-11-20</td>
        </tr>
        <tr class="2013-11-15">
            <td>2013-11-15</td>
        </tr>
        <tr class="2013-11-17">
            <td>2013-11-17</td>
        </tr>
        <tr class="2013-11-20">
            <td>2013-11-20</td>
        </tr>
    </tbody>
</table>

Fiddle: http://jsfiddle.net/fEM8X/9/ 小提琴: http//jsfiddle.net/fEM8X/9/

Closest will select the ancestor or self (first one that matches the selector), but you want to select the sibling of ancestor ( .widget ) of the checked check box. 最近将选择祖先或自我(第一个匹配选择器),但您要选中已选中复选框的祖先( .widget )的兄弟。 So Try: 所以尝试:

$('input[type = checkbox]').change(function () {
    var self = this;
     $(self).closest('.widget').next('table').find('tbody tr').filter('.' + self.value).toggle(self.checked);
});

Demo 演示

But in this case you can just do the following since you use the same classes for the targets: 但在这种情况下,您可以执行以下操作,因为您对目标使用相同的类:

 $('.' + this.value).toggle(self.checked);

Demo 演示

Use this.value of the checked box and use it as class to toggle. 使用复选框的this.value并将其用作要切换的类。 You could simply do this. 你可以这么做。

$('input[type = checkbox]').change(function () {
    var myclass = this.value;
    $('.' + myclass).toggle();
});

jsFIDDLE DEMO jsFIDDLE DEMO

you can just add a css to tr, see this DEMO 你可以只为tr添加一个css,看看这个DEMO

$('input[type="checkbox"]').change(function () {    
    var self = this;
    $("table tr."+$(this).val()).css({display: self.checked?"block":"none"});
});

I updated your fiddle 我更新了你的小提琴

Basically, your selectors were not correct: 基本上,您的选择器不正确:

$('input[type = checkbox]').change(function () {
    var valu = $(this).val();
    var ischecked = $(this).is(":checked");

    if( ischecked ){
        $('.' + valu).show();
    }else{
        $('.' + valu).hide();
    }
});

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