[英]Ajax request won't work without sending data
I'm trying to make an AJAX request to a PHP script for a simple logout. 我正在尝试向PHP脚本发出一个AJAX请求以进行简单的注销。 The PHP just does the following:
PHP只执行以下操作:
<?php
session_start();
unset($_SESSION['autorizzato']);
$arr=array('result'=>"logout effettuato con successo");
$ris=json_encode($arr);
echo $ris;
?>
While the AJAX request looks something like this: 虽然AJAX请求看起来像这样:
$.ajax({
type: 'POST',
url: 'logout.php',
async: false
}).success(function(response){
if (response['result']=="logout effettuato con successo")
{
change();
}
else alert("Errore nel logout");
});
});
Problem is that resonse['result'] looks like it's unset. 问题是,共鸣['结果']看起来像是没有设置。 The curious thing is that if I add to the AJAX request a data string (like this:
奇怪的是,如果我向AJAX请求添加一个数据字符串(如下所示:
$.ajax({
type: 'POST',
url: 'logout.php',
async: false,
dataType: 'json',
data: sendstr
}).success(function(response){
if (response['result']=="logout effettuato con successo")
{
change();
}
else alert("Errore nel logout");
});
});
where sendstr is a simple JSON stringified object. 其中sendingtr是一个简单的JSON字符串化对象。 Anyone knows why?
谁知道为什么? Thank you in advance :)
先感谢您 :)
your success function should do like 你的成功功能应该是这样的
success(function(response){
var returnsult=JSON.parse(response);
if (returnsult.result=="logout effettuato con successo")
{
change();
}
else alert("Errore nel logout");
});
Either you go this way: 你要么这样:
$.ajax({
type: 'POST',
url: 'logout.php',
async: false
}).success(function(response){
response=JSON.parse(response);//convert JSON string to JS object
if (response['result']=="logout effettuato con successo")
{
change();
}
else alert("Errore nel logout");
});
});
Or 要么
$.ajax({
type: 'POST',
url: 'logout.php',
async: false,
dataType: 'json' /* Tell jQuery you are expecting JSON */
}).success(function(response){
if (response['result']=="logout effettuato con successo")
{
change();
}
else alert("Errore nel logout");
});
});
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