在C中传递一个结构槽几个函数？

Question

In my code I got a struct of this kind and two functions:

typedef struct {
    char team;
    int score;
} Player;

myfunc1 (Player *players) {
    players->score = 105;
    myfunc(?);
}

myfunc2(?) {
    //change again points and team character
}

And in main I create an array of that struct and pass it to a function:

int main () {
    Player players[2]

    myfunc1(players)

}

I get to work the first function, but I don't know what argument I should pass from the first to the second to modify the array of players[2] created in main.

Answer 1

You can again use a simple pointer to access the data from players :

void myfunc2 (Player *player)
{
    players->score = 123;
}

Call it from your myfunc1 like this:

myfunc2(players);

You will actually pass an address to Player structure stored in pointer Player* players (in function myfunc1 ) into local pointer variable Player *player in function myfunc2 .

To modify players[1] in your main function, call myfunc1 like this:

int main () {
    Player players[2]

    myfunc1(&players[1]); // & = give an address to your struct
}

Be careful about array indexes, they do start from zero, so if yu have an array with capacity of two ( Player players[2] ) then there are only two valid indexes: 0 an 1 . If you access indexes beyound the capacity your code will sooner or later crash.