在Python中使用subprocess.check_output时出错

Question

I am at a very basic level in Python, and I'm trying to learn how to use the subprocess module. I have a simple calculator program called x.py that takes in a number, multiplies it by 2, and returns the result. I am trying to execute that simple program from IDLE with the following two lines of code, but I get errors. The number 5 is the number I'm trying to feed into x.py to get a result. Would someone mind helping me understand what I'm doing wrong and help me get it right? Thanks!

import subprocess

result = subprocess.check_output(["C:\\Users\\Kyle\\Desktop\\x.py",5])

Traceback (most recent call last):
File "<pyshell#3>", line 1, in <module>
result = subprocess.check_output(["C:\\Users\\Kyle\\Desktop\\x.py",5])
File "C:\Python27\lib\subprocess.py", line 537, in check_output
process = Popen(stdout=PIPE, *popenargs, **kwargs)
File "C:\Python27\lib\subprocess.py", line 679, in __init__
errread, errwrite)
File "C:\Python27\lib\subprocess.py", line 855, in _execute_child
args = list2cmdline(args)
File "C:\Python27\lib\subprocess.py", line 587, in list2cmdline
needquote = (" " in arg) or ("\t" in arg) or not arg
TypeError: argument of type 'int' is not iterable

Answer 1

Pass 5 as a string:

import sys
result = subprocess.check_output([sys.executable, "C:\\Users\\Kyle\\Desktop\\x.py", '5'])