[英]Java cURL alternative with HttpURLConnection
I was asked to port a PHP module I was writing to Java. 我被要求移植我正在编写的Java PHP模块。 I was previously using PHP's native cURL library, now trying to achieve the same action with HttpURLConnection.
我以前使用的是PHP的本机cURL库,现在尝试使用HttpURLConnection实现相同的操作。
Here's the call I want to do with cURL: 这是我要使用cURL进行的呼叫:
curl -u 'ExactID:Password' \
-H 'Content-Type: application/json; charset=UTF-8' \
-H 'Accept: application/json' \
-d '{
"transaction_type":"00",
"amount":"15.75",
"cardholder_name":"PaulTest",
"transarmor_token":"3000",
"credit_card_type":"Visa",
"cc_expiry":"0016",
}' \
https://api.demo.globalgatewaye4.firstdata.com/transaction/v11
Here's what I have in Java, which returns a HTTP 400 error. 这是我在Java中所拥有的东西,它返回HTTP 400错误。 Any ideas?
有任何想法吗?
public static void main(String[] args) {
URL url = new URL("https://api.demo.globalgatewaye4.firstdata.com/transaction/v11");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
conn.setRequestProperty("Accept", "application/json");
String userpass = "ExactID" + ":" + "Password";
String basicAuth = "Basic " + new String(new Base64().encode(userpass.getBytes()));
conn.setRequestProperty ("Authorization", basicAuth);
JSONObject obj = new JSONObject();
obj.put("transaction_type", "00");
obj.put("amount", "10");
obj.put("cardholder_name", "PaulTest");
obj.put("transarmor_token", "3000");
obj.put("cc_expiry", "0016");
obj.put("credit_card_type", "Visa");
String input = obj.toString();
System.out.println(input);
OutputStream os = conn.getOutputStream();
os.write(input.getBytes());
os.flush();
if (conn.getResponseCode() != HttpURLConnection.HTTP_CREATED) {
throw new RuntimeException("Failed : HTTP error code : "+ conn.getResponseCode() + conn.getResponseMessage());
}
One ambiguity in your java code is on string to byte array encoding. Java代码中的一个歧义是字符串到字节数组编码。 By default java will use your default platform encoding, but it's a good practice to express it explicitly because it often lead to hard to track bug
默认情况下,java将使用您的默认平台编码,但这是一种明确表达的好习惯,因为它通常会导致难以跟踪的错误
String basicAuth = "Basic " + new String(new Base64().encode(userpass.getBytes("ISO-8859-1")));
To be sure also check the encoded base 64 value generated by java on curl by using 还要确保使用以下命令检查curl上java生成的编码基数64值:
-H 'Authorization: Basic ....`
Instead of -u
代替
-u
Also I'd try to cast the created URLConnection to HttpsURLConnection. 另外,我尝试将创建的URLConnection强制转换为HttpsURLConnection。 Thay may/not make difference
Thay可能/没有影响
HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
After tinkering around, I made two mistakes: 修补之后,我犯了两个错误:
For this POST method, basic authentication was not required. 对于此POST方法,不需要基本身份验证。 The user & pw goes into the JSON body along with the other parameters.
用户&pw与其他参数一起进入JSON正文。
Also, my "transarmor_token" field needed to be 16 digits. 另外,我的“ transarmor_token”字段必须为16位数字。
Conclusion: HttpURLConnection is a great cURL alternative. 结论:HttpURLConnection是一个很好的cURL替代方案。 Forget about using the curl-java binding.
忘记使用curl-java绑定了。
Thanks! 谢谢!
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