MySQL查询无法正常工作。 没有给出预期的结果

Question

I have a database where there are 4 field to do query.

1. topup
2. totala
3. totalb
4. totalc

I am running the mysql query which is supposed to return 4 rows. But returning nothing. Following is my query:

$qry=mysql_query("SELECT id FROM ".user." WHERE `topup` >'0' AND `totala`>='9' AND  `totalb`>='9' AND  `totalc`>='9'");
while($res=mysql_fetch_row($qry)){
    echo $res['0'];
}

what is the wrong? And main problem is if I run any one query

eg: WHERE totala >='9'

then it is working, but not taking all query

Answer 1

Your query will fetch rows in which all your condition are true simultaneously.

It will fetch the row with topup = 1 and totala = 10 and totalb = 10 and totalc = 10 but won't fetch the row topup = 0 and totala = 10 and totalb = 10 and totalc = 10 because of topup not greater than zero.

If you want to fetch row with ANY of this condition you need to use OR statement instead of AND.

$qry=mysql_query("SELECT id FROM ".user." WHERE `topup` >'0' OR `totala`>='9' OR `totalb`>='9' OR `totalc`>='9'");