[英]Selecting rows with max value in range
I have the followng data: 我有以下数据:
+----+---------+---------------------+-------+
| id | site_id | datetime | views |
+----+---------+---------------------+-------+
| 1 | 1 | 2013-11-01 23:59:59 | 12 |
| 2 | 1 | 2013-11-02 23:59:59 | 15 |
| 3 | 1 | 2013-11-03 23:59:59 | 18 |
| 4 | 1 | 2013-11-04 23:59:59 | 29 |
| 5 | 1 | 2013-11-05 23:59:59 | 38 |
| 6 | 1 | 2013-11-05 12:59:59 | 40 |
| 7 | 1 | 2013-11-06 23:59:59 | 45 |
| 8 | 1 | 2013-11-07 23:59:59 | 49 |
| 9 | 1 | 2013-11-08 23:59:59 | 52 |
| 10 | 2 | 2013-11-04 23:59:59 | 25 |
| 11 | 2 | 2013-11-05 21:59:59 | 42 |
| 12 | 2 | 2013-11-06 23:59:59 | 60 |
| 13 | 2 | 2013-11-07 23:59:59 | 75 |
| 14 | 2 | 2013-11-08 23:59:59 | 86 |
| 15 | 2 | 2013-11-09 23:59:59 | 90 |
| 16 | 2 | 2013-11-10 23:59:59 | 92 |
| 17 | 2 | 2013-11-11 23:42:59 | 98 |
+----+---------+---------------------+-------+
I would pass a day and wish to get the rows with the highest time in the given day or if there`s no records for this site for this day, the last available row in the past. 我希望通过一天,希望获得给定日期中时间最长的行,或者如果该站点在这一天中没有记录,则为过去的最后一行。
eg for 2013-11-01
例如对于
2013-11-01
+----+---------+---------------------+-------+
| id | site_id | datetime | views |
+----+---------+---------------------+-------+
| 1 | 1 | 2013-11-01 23:59:59 | 12 |
+----+---------+---------------------+-------+
for 2013-11-05
为
2013-11-05
+----+---------+---------------------+-------+
| id | site_id | datetime | views |
+----+---------+---------------------+-------+
| 5 | 1 | 2013-11-05 23:59:59 | 38 |
| 11 | 2 | 2013-11-05 21:59:59 | 42 |
+----+---------+---------------------+-------+
and for 2013-11-10
而对于
2013-11-10
+----+---------+---------------------+-------+
| id | site_id | datetime | views |
+----+---------+---------------------+-------+
| 9 | 1 | 2013-11-08 23:59:59 | 52 |
| 16 | 2 | 2013-11-10 23:59:59 | 92 |
+----+---------+---------------------+-------+
Thanks in advance. 提前致谢。
You can try this: 您可以尝试以下方法:
SELECT a.id,a.site_id,b.maxDate,a.views
FROM table1 a
INNER JOIN (
SELECT site_id ,MAX(datetime) as maxDate
FROM table1
WHERE datetime < DATEYOUWANTTOSEE + INTERVAL 1 DAY
GROUP BY site_id
) b ON a.site_id = b.site_id AND a.datetime = b.maxDate
The inner query will get you the MAX(datetime) for each site_id. 内部查询将为您获取每个site_id的MAX(datetime)。 Then you join it with your table to get the rest of the information.
然后,将其与表连接起来以获取其余信息。
SELECT * FROM <tablename> WHERE datetime = <datetime> ORDER BY datetime DESC LIMIT 2
I believe this should work: 我相信这应该有效:
SELECT SUBSTRING(`datetime`, 1, 10) AS date, MAX(`views`)
FROM table
GROUP BY SUBSTRING(`datetime`, 1, 10)
If you need the id/site_id as well, write it in your post, as it is not clear 如果还需要id / site_id,请将其写在您的帖子中,因为目前尚不清楚
SQLFiddle to show you the result: http://sqlfiddle.com/#!2/e0ccb3/1 SQLFiddle向您显示结果: http ://sqlfiddle.com/#!2/e0ccb3/1
You data and examples do not really match themselves, nor the description, but what you probably are looking for is this: 您的数据和示例并没有真正匹配它们,也没有描述,但您可能正在寻找的是:
Select top 1 *
from table
where date(datetime) <= date(@PARAMETER)
order by datetime desc 按日期时间顺序排序
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