Web.xml导致Tomcat7失败

Question

I have a basic servlet.

I using tomcat 7 to run it.

The server contains 3 files:

1. file.jsp - prints the date

2. WebController - the servlet.

3. web.xml - configuration file.

web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <servlet>
          <servlet-name>file.jsp</servlet-name>
          <jsp-file>file.jsp</jsp-file>
    </servlet>
    <servlet-mapping>
          <servlet-name>file.jsp</servlet-name>
          <url-pattern>/about</url-pattern>
    </servlet-mapping>
</web-app>

When I remove the <servlet> and <servlet-mapping> from the web.xml file, the servlet runs good.

When web.xml is as the above, I'm getting the following error message:

'Staring Tomcat v7.0 Server at localhost' has encountered a problem.

Server Tomcat v7.0 Server at localhost failed to start.

I'm using eclipse. what is the problem in my web.xml file? thanks in advance!

Edit:

This is my project:

Update:

current version of web.xml :

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <servlet>
          <servlet-name>file.jsp</servlet-name>
          <jsp-file>/file.jsp</jsp-file>
    </servlet>

    <servlet>
        <servlet-name>WebController</servlet-name>
        <servlet-class>WebController</servlet-class>
    </servlet>

    <servlet-mapping>
          <servlet-name>file.jsp</servlet-name>
          <url-pattern>/about</url-pattern>
    </servlet-mapping>
</web-app>

Answer 1

Your jsp file must not be in WEB-INF. Place it in the root of your project

Update the web.xml as follows:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
    http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <servlet>
      <servlet-name>file.jsp</servlet-name>
      <jsp-file>/file.jsp</jsp-file>
    </servlet>
    <servlet-mapping>
      <servlet-name>file.jsp</servlet-name>
      <url-pattern>/about</url-pattern>
    </servlet-mapping>
</web-app>

here is how your project should look like:

/myjspapp
   /file.jsp
   /WEB-INF
      /web.xml

you can now access your jsp at the following url: localhost:8080/myjspapp/about

Answer 2

One possible format for servlet mapping in the web.xml file looks like this:

<servlet>
    <servlet-name>com.example.file_jsp</servlet-name>
    <servlet-class>com.example.file_jsp</servlet-class>
</servlet>

<servlet-mapping>
    <servlet-name>com.example.file_jsp</servlet-name>
    <url-pattern>/file.jsp</url-pattern>
</servlet-mapping>

The class name comes from the JSP file name and this part of your build.xml:

<jasper2 
  validateXml="false"
  uriroot="web"
  package="com.example"
  webXmlFragment="build/web/WEB-INF/generated_web.xml"
  outputDir="build/src" />

Answer 3

This is answer is similar to as ph's but as you said that it was giving you status 500 so, worked the problem out for you...

Try putting the JSP file in webcontent folder (For eclipse only) and then follow your example.

I have worked on your example and it gives me proper output.

Below is my project structure in eclipse:-

Below is configured web.xml file:-

After running the server, and requesting the URL Pattern "/about" I am getting my output of JSP.

Please try and let me know... Hope this helps