PHP-查找目录中与特定字符串匹配的所有所有文件并放入数组

Question

I have a directory of images on a server that customers have uploaded. I need to be able to get all files that match a certain string or item code and put them inside an array. Filenames and extensions can always vary but each file will always have an 8 digit item code in the filename. So for instance say in my directory i have:

/images/

62115465.jpg
62115465-02.jpg
62115465-07.jpg
13452766.png
56773392.jpeg
56773392-avatar.jpg

I want to be able to pull out all the files that match the 8 digit item code so:

//all images that have 62115465 in the file name would give me

62115465.jpg
62115465-02.jpg
62115465-07.jpg

//or all images that have 56773392 in the file name would give me

56773392.jpeg
56773392-avatar.jpg

and then want them in an array like so:

$all_files = array(
  '62115465.jpg',
  '62115465-02.jpg',
  '62115465-07.jpg'
);

I tried using the glob() function as below which can match some files like the 62115465.jpg but doesnt pick up the 2 other files with the -02 and -07 tags

$files = glob('62115465.'.*');

Answer 1

glob('62115465*');

note the removal of the . . glob() essentially replicates doing something like dir *.txt at a command prompt.

Answer 2

I know this question was answered already, but to the novice/intermediate coder, or anyone new to the glob() function ( AHEM ME COUGH ), it's pretty unclear what's going on here. So, here's a full script that I cobbled together to do pretty much the same thing the OP asked for- search through a directory for all files beginning with the target prefix and add them to an array.:

<?php
$imgs = array();
$dir =  $_SERVER['DOCUMENT_ROOT'].'/path/to/your/images';
$prefix = 'your-prefix_string-_-';
chdir($dir);
$matches = glob("$prefix*");
if(is_array($matches) && !empty($matches)){
    foreach($matches as $match){
        $imgs[] = $match;
    }
}
?>

Answer 3

你可以试试这个吗

 $files = glob('62115465.*');

Answer 4

Try like this-

$files = glob("[^62115465]*.*);

Or like this:

$files = glob("62115465*.*);