如何计算JavaScript中两个日期之间的年，月和天的差异？

Question

How can I calculate the difference between two days telling me the remaining years remaining months and remaining days?

Example: From: Oct 1 2013 To: Nov 15 2013

Output: 1 Month and 15 Days

I've tried momentjs but it display the whole months and days, like 1 Month, 45 Days. I also tried this function but it displays the same thing:

var diff = Math.floor(end_date.getTime() - start_date.getTime());
var day = 1000* 60 * 60 * 24;
var days = Math.floor(diff/day);
var months = Math.floor(days/31);
var years = Math.floor(months/12);

var message = days + " days " 
message += months + " motnhs "

Answer 1

Days seems to be the trickiest calculation, otherwise it's pretty straight-forward. Subtract the current milliseconds from the target milliseconds to get the duration in milliseconds. Then for each value but days, take the floor of the duration divided by the number of milliseconds in either a year, month, hour, minute or second. This gives you the number or years, months, hours, minutes or seconds in the duration. Finally, take the modulus of each of the values.

For days, subtract the number of years and months in milliseconds from the duration to get the remaining milliseconds, then take the floor of the remaining milliseconds divided by the number of milliseconds in a day.

 function countdown(targetDate) { var nowMillis = new Date().getTime(); var targetMillis = targetDate.getTime(); var duration = targetMillis - nowMillis; var years = Math.floor(duration / 3.154e+10); var durationMinusYears = duration - (years * 3.154e+10); var months = Math.floor(duration / 2.628e+9) % 12; var durationMinusMonths = durationMinusYears - (months * 2.628e+9); var days = Math.floor(durationMinusMonths / 8.64e+7); var hours = Math.floor(duration / 3.6e+6 ) % 24; var mins = Math.floor(duration / 60000 ) % 60; var secs = Math.floor(duration / 1000 ) % 60; return [ years, months, days, hours, mins, secs ]; } console.log('Count down until IE11 is no longer supported => ' + countdown(new Date(2020, 9, 13, 0, 0))); 

Answer 2

You have to do some estimating (a month is 31 days, a year is 365 days, etc) AND you have to subtract the number you've already used from diff as you go along.

var diff = Math.floor(end_date.getTime() - start_date.getTime());
var 
    lengthOfDayInSeconds = 1000* 60 * 60 * 24,
    lengthOfMonthInSeconds = lengthOfDayInSeconds*31,
    lengthOfYearInSeconds = lengthOfDayInSeconds*365;

var yearsBetween = Math.floor(diff/lengthOfYearInSeconds);
diff -= yearsBetween*lengthOfYearInSeconds;

var monthsBetween = Math.floor(diff/lengthOfMonthInSeconds);
diff -= monthsBetween*lengthOfMonthInSeconds;

var daysBetween = Math.floor(diff/lengthOfDayInSeconds);

message = yearsBetween + ' years '+ monthsBetween + ' months ' + daysBetween + ' days';

The difference between 1/1/2000 and 7/16/2001 is, by this code: 1 years 6 months 16 days

Answer 3

Got the answer here: Convert a number (of days) to days, months and years with jQuery

With this function:

function humanise(total_days)
{
    //var total_days = 1001;
    var date_current = new Date();
    var utime_target = date_current.getTime() + total_days*86400*1000;
    var date_target = new Date(utime_target);

    var diff_year  = parseInt(date_target.getUTCFullYear() - date_current.getUTCFullYear());
    var diff_month = parseInt(date_target.getUTCMonth() - date_current.getUTCMonth());
    var diff_day   = parseInt(date_target.getUTCDate() - date_current.getUTCDate());

    var days_in_month = [31, (date_target.getUTCFullYear()%4?29:28), 31, 30, 31, 30, 31, 31, 30, 31, 30, 31];
    var date_string = "";
    while(true)
    {
        date_string = "";
        date_string += (diff_year>0?diff_year + "Y":"");

        if(diff_month<0){diff_year -= 1; diff_month += 12; continue;}
        date_string += (diff_month>0?diff_month + "M":"");

        if(diff_day<0){diff_month -= 1; diff_day += days_in_month[((11+date_target.getUTCMonth())%12)]; continue;}
        date_string += (diff_day>0?diff_day + "D":"");
        break;
    }
    return date_string;
}

Answer 4

I'm using this to get the value. modification from this link

function get_number_of_days(firstDate, secondDate) {
   var diff_year  = parseInt(secondDate.getFullYear() - firstDate.getFullYear());
   var diff_month = parseInt(secondDate.getMonth() - firstDate.getMonth());
   var diff_day   = parseInt(secondDate.getDate() - firstDate.getDate());

   var hash_date = {};

   while(true) {
     hash_date = {};
     hash_date["y"] = diff_year;

     if(diff_month < 0) {
       diff_year -= 1; 
       diff_month += 12; 
       continue;
     }
     hash_date["m"] = diff_month;

     if(diff_day < 0) {
       diff_month -= 1; 
       diff_day += get_month_length(secondDate.getFullYear(), secondDate.getMonth());
       continue;
     }
     hash_date["d"] = diff_day;
     break;
   }

   return hash_date;
}

function get_month_length(year, month) {
    var hour = 1000 * 60 * 60;
    var day = hour * 24;
    var this_month = new Date(year, month, 1);
    var next_month = new Date(year, month + 1, 1);
    var length = Math.ceil((next_month.getTime() - this_month.getTime() - hour)/day);

   return length;
}