[英]no match returned for this regular expression
I am using raw string notation to express a fairly simple regular expression and I am not getting a match object. 我正在使用原始字符串表示法来表达一个相当简单的正则表达式,但没有得到匹配对象。 Shell transcript follows: Shell脚本如下:
[~/Documents/Programming/rlm]$ python
python
Python 2.7.5 (default, Aug 25 2013, 00:04:04)
[GCC 4.2.1 Compatible Apple LLVM 5.0 (clang-500.0.68)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> s = 'bob2323'
s = 'bob2323'
>>> import re
import re
>>> re.match(r'\d+', s)
re.match(r'\d+', s)
>>>
Use re.search
instead of re.match
, because re.match
only matches from the start of the string.: 使用re.search
而不是re.match
,因为re.match
只匹配字符串的开头。
>>> re.search(r'\d+', s)
<_sre.SRE_Match object at 0xb5eefbf0>
re.match
vs re.search
: re.match
VS re.search
:
re.match()
checks for a match only at the beginning of the string, whilere.search()
checks for a match anywhere in the string.re.match()
仅在字符串的开头检查匹配项,而re.search()
在字符串的任何位置检查匹配项。
You need to use re.search
. 您需要使用re.search
。 re.match
only attempts to match starting at the beginning of the string. re.match
仅尝试从字符串开头开始进行匹配。 However, re.search
will search through the entire string looking for a substring that matches the pattern. 但是, re.search
将搜索整个字符串以查找与模式匹配的子字符串。
>>> import re
>>> s = "bob2323"
>>> re.match(r'\d+', s)
>>> re.search(r'\d+', s)
<_sre.SRE_Match object at 0x7f4d19beb988>
>>>
See search() vs. match() in the docs for more information 有关更多信息,请参见文档中的search()与match() 。
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