在php中显示SQL查询结果

Question

I'm tring to diplay results in php from sql database MySQL statement is correct and does what i want in phpMyAdmin but for some reason my code breaks in the webpage

here is the code

require_once('db.php');  
$sql="SELECT * FROM  modul1open WHERE idM1O>=(SELECT FLOOR( MAX( idM1O ) * RAND( ) )  FROM  modul1open) 
ORDER BY idM1O LIMIT 1"

$result = mysql_query($sql);
echo [$result];

• and here is what i get

In general I need random number limited from min to max by the table id

Answer 1

You need to fetch the data from each row of the resultset obtained from the query. You can use mysql_fetch_array() for this.

// Process all rows
while($row = mysql_fetch_array($result)) {
    echo $row['column_name']; // Print a single column data
    echo print_r($row);       // Print the entire row data
}

Change your code to this :

require_once('db.php');  
$sql="SELECT * FROM  modul1open WHERE idM1O>=(SELECT FLOOR( MAX( idM1O ) * RAND( ) )  FROM  modul1open) 
ORDER BY idM1O LIMIT 1"

$result = mysql_query($sql);
while($row = mysql_fetch_array($result)) {
    echo $row['fieldname']; 
}

Answer 2

You need to do a while loop to get the result from the SQL query, like this:

require_once('db.php');  
$sql="SELECT * FROM  modul1open WHERE idM1O>=(SELECT FLOOR( MAX( idM1O ) * RAND( ) )    
FROM modul1open) ORDER BY idM1O LIMIT 1";

$result = mysql_query($sql);

while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {

    // If you want to display all results from the query at once:
    print_r($row);

    // If you want to display the results one by one
    echo $row['column1'];
    echo $row['column2']; // etc..

}

Also I would strongly recommend not using mysql_* since it's deprecated. Instead use the mysqli or PDO extension. You can read more about that here .

Answer 3

You cannot directly see the query result using mysql_query(). It just fires the query in mysql, nothing else.

For getting the result you have to add a lil things in your script like

require_once('db.php');  
 $sql="SELECT * FROM  modul1open WHERE idM1O>=(SELECT FLOOR( MAX( idM1O ) * RAND( ) )  FROM  modul1open) ORDER BY idM1O LIMIT 1";

 $result = mysql_query($sql);
 //echo [$result];
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    print_r($row);
}

This will give you result.

Answer 4

Strangely, none of the while loops in the other answers worked for me, they did not throw an error, but their echo was empty. It worked when using foreach instead:

foreach($result as $row) {
    //echo $row['column_name']; // Print a single column data
    echo print_r($row);       // Print the entire row data
}

Idea from: PDO looping through and printing fetchAll

Answer 5

I had to change

$result = mysql_query($sql);

to

$result = $conn->query($sql);

and then use the foreach (thanks to questionto42)

$result = $conn->query($sql);
foreach($result as $row) {
    echo $row['column_name'];
}

Don't know if it matters but, I'm on a hosting company with: Apache Version 2.4.51 PHP Version 7.3.33 MySQL Version 5.6.41-84.1

Answer 6

$query ="
  SELECT 
   *
  FROM
    users
";
die($query);

In this case your query print on the browser copy this query and run on SQL Server.