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StringTokenizer数组

[英]StringTokenizer array

Java. Java的。 So I want to input an array of integers and then print out the max value using StringTokenizer. 所以我想输入一个整数数组,然后使用StringTokenizer打印出最大值。 I know how to do this using integers, but when I try to do it with an array the String to int command (Integer.parseInt) fails me - cannot convert from int to int[]. 我知道如何使用整数来执行此操作,但是当我尝试使用数组来执行此操作时,将字符串转换为int命令(Integer.parseInt)失败了-无法从int转换为int []。

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        String strTmp;
        StringTokenizer strTok;
        while ((strTmp = in.readLine()) != null && strTmp.length() != 0) {
            strTok = new StringTokenizer(strTmp);

        int[] c;

        c = Integer.parseInt(strTok.nextToken());

        int max = 0;
        for (int i = 0; i < c.length; i++) {
            if (c[i] > max) {
                max = c[i];
            }
        }
        System.out.println(max);
    }
}
}

How do I go about solving this or are there other commands I should be using? 我该如何解决该问题,或者应该使用其他命令?

You seem to be confused about whether you actually want an array or not. 您似乎对实际上是否需要数组感到困惑。 You're parsing a single value , but trying to assign that int to c which is an array variable. 您正在解析一个 ,但尝试将该int分配给c ,它是一个数组变量。 You don't really need one, as you only need to remember the current maximum, and the value you've just parsed: 您实际上并不需要一个,因为您只需要记住当前的最大值以及刚刚解析的值即可:

int max = Integer.MIN_VALUE;
while (strTok.hasMoreTokens()) {
    int value = Integer.parseInt(strTok.nextToken());
    if (value > max) {
        max = value;
    }
}

If you really want an array, then you'll need to know how many tokens there are before you parse them, which is tricky. 如果您真的想要一个数组,那么在解析它们之前,您需要知道有多少个令牌,这很棘手。

Another alternative would be to create a List<Integer> : 另一种选择是创建一个List<Integer>

// First parse everything...
List<Integer> values = new ArrayList<>();
while (strTok.hasMoreTokens()) {
    values.add(Integer.parse(strTok.nextToken());
}

// Then you can find the maximum value in the list

Personally I prefer the first approach, if you only need to find the maximum value. 就个人而言,如果您只需要找到最大值,则我倾向于第一种方法。

 int[] c;

 c = Integer.parseInt(strTok.nextToken());

You are trying to assign a single Integer object to an array of int . 您试图将单个Integer对象分配给int数组。

Rather, use int[index] = Integer.parseInt(strTok.nextToken()); 而是使用int[index] = Integer.parseInt(strTok.nextToken());

Integer.parseInt(String) returns an integer, not an Integer array . Integer.parseInt(String)返回一个整数,而不是Integer array You have to store the return value Integer in an int variable like 您必须将返回值Integer存储在一个int变量中,例如

int i = Integer.parseInt(String);

You have to iterate the integer array and set it's index value to the returned integer value 您必须迭代整数数组并将其索引值设置为返回的整数值

for (int i = 0; i < c.length; i++) {
           c[i] = Integer.parseInt(strTok.nextToken());
            if (c[i] > max) {
                max = c[i];
            }
        }

Hope this helps! 希望这可以帮助!

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