[英]Match floats in Ruby with regexp
I need to extract a float from a string in Ruby, but if I try to extract it with the normal \\d I of course don't fetch the digits in front of the ",". 我需要从Ruby中的字符串中提取浮点数,但是如果我尝试使用普通符号提取它,我当然不会获取“,”前面的数字。
"3,25 år -".match((\d+)\s?år\s?-)[1] => # "25"
Is there an easy way to fetch the whole number? 有没有一种简单的方法来获取整数?
"3,25 år -".match(/([\d,]+)\s?år\s?-/)[1] => # "3,25"
Pay attention that your code also had another error. 注意你的代码也有另一个错误。 You were missing the regex delimiters.
你错过了正则表达式分隔符。 It should be
它应该是
match(/.../)
not 不
match(...)
You are missing the forward slashes /
around the regular expression. 您缺少正则表达式的正斜杠
/
周围。
Apart of that, this will return what you want: 除此之外,这将返回你想要的:
"3,25 år -".match(/(\d+(?:,\d+)?)\s?år\s?-/)[1] => # "3,25"
As a side note, the above will match both positive integers and floats. 作为旁注,上面将匹配正整数和浮点数。 If you are sure you will always have floats, simplify it like that:
如果您确定您将始终拥有浮动,请将其简化为:
"3,25 år -".match(/(\d+,\d+)\s?år\s?-/)[1] => # "3,25"
Finally, I would propose you to get used to the [0-9]
notation for digits instead of \\d
, ready why here , so finally try this: 最后,我建议你习惯于
[0-9]
表示数字而不是\\d
, 为这里准备好了 ,所以最后试试这个:
"3,25 år -".match(/([0-9]+,[0-9]+)\s?år\s?-/)[1] => # "3,25"
PS. PS。 I would suggest you to avoid the
[\\d,]+
solutions since this regular expression can match also non-numbers, eg it will match 1,,1
or 1,
or ,1
. 我建议你避免
[\\d,]+
解决方案,因为这个正则表达式也可以匹配非数字,例如它将匹配1,,1
或1,
或,1
。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.