Excel：如何查找列的第一行的值，具体取决于在同一列的另一行中查找给定数字的位置
[英]Excel: How to find the first row's value of a column depending on where to find a given number in another row of the same column
问题描述
Imagine a 100x100 table. 
想象一张100x100的桌子。 I have to find a given value in the first column. 我必须在第一列中找到给定的值。 Then I have to check the row contains that given value, and I have to find the column where the value is 1 (every row has only one cell with value 1), and I need the first row's value of that column. 然后，我必须检查包含给定值的行，并且必须找到该值为1的列（每行只有一个值为1的单元格），并且我需要该列的第一行的值。 I've tried several lookup functions (vlookup, hlookup, index match match, etc). 我尝试了几种查找功能（vlookup，hlookup，索引匹配匹配等）。 No results. 没结果。 Is it possible using only functions and no VBA at all? 是否可以仅使用功能而不使用VBA？
1 个解决方案
解决方案1
1 已采纳 2013-12-02 00:40:55
I'd prefer to use INDEX rather than INDIRECT , it's not volatile and it's more robust in dealing with added rows or columns than "hardcoded" values like "B" and "D", so assuming data in A1:Z100 you can use this formula for the match, assuming a search value of "x" 我宁愿使用INDEX而不是INDIRECT ，它不易变，并且在处理添加的行或列方面比“ B”和“ D”之类的“硬编码”值更健壮，因此假设A1:Z100数据可以使用匹配的公式，假设搜索值为“ x”
=MATCH(1,INDEX(B2:Z100,MATCH("x",A2:A100,0),0),0)
...and you can add an extra INDEX function to retrieve the first row value for that column ...并且您可以添加一个额外的INDEX函数来检索该列的第一行值
=INDEX(B1:Z1,MATCH(1,INDEX(B2:Z100,MATCH("x",A2:A100,0),0),0))
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