[英]How can i stop a socket thread in Python?
In Python 3.3.3, i create a thread to listen some connection to the socket.It likes this: 在Python 3.3.3中,我创建了一个线程来侦听与套接字的某些连接。它是这样的:
import threading
import socket
import time
Host = ''
Port = 50000
flag = False
class ServerThread(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self._sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
def run(self):
try:
self._sock.bind((Host, Port))
self._sock.listen(5)
while True:
conn, addr = self._sock.accept()
print('Connected by', addr)
except socket.error as msg:
print(msg)
except Exception as e:
print(str(e))
finally:
self._sock.close()
def exit(self):
self._sock.close()
def TargetFunc(vlock):
vlock.acquire()
flag = True
vlock.release()
def main():
sthread = ServerThread()
sthread.start()
vlock = threading.Lock()
time.sleep(10)
vthread = threading.Thread(target = TargetFunc, args = (vlock, ))
vthread.start()
while True:
vlock.acquire()
if flag:
sthread.exit()
vlock.release()
break
vlock.release()
sthread.join()
vthread.join()
if __name__ == '__main__':
main()
There are two threads, one is listening socket, the other is to set a flag. 有两个线程,一个是侦听套接字,另一个是设置标志。 When the flag is True, close the socket, then raise a socket error and catch it, so the listening socket terminates.But why it does not work this.
当该标志为True时,关闭套接字,然后引发套接字错误并捕获它,以便监听套接字终止,但是为什么它不起作用。
Thanks! 谢谢!
self._sock.accept()
is blocking. self._sock.accept()
正在阻止。 So it will wait until somebody connects. 因此它将等待直到有人连接。 You should use a nonblocking variant (or blocking but with a time-out).
您应使用非阻塞变体(或阻塞但超时)。 So that you can check the exit conditions.
这样就可以检查退出条件。
Alternatively you could force an exception in the ServerThread. 或者,您可以在ServerThread中强制执行异常。
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