[英]python: chain elements of a tuple in a list of tuples
I want to find combinations of elements in a string. 我想找到字符串中元素的组合。 baseString
is of variable length eg 'tbyhn' or 'tg' or so on. baseString
的长度可变,例如'tbyhn'或'tg'等。
I tried: 我试过了:
import itertools
baseString = 'tgby'
prd = [it for it in itertools.product(base,repeat=len(baseString)-1)]
prd
is a list that looks like this: prd
是一个看起来像这样的列表:
[('t', 't', 't'), ('t', 't', 'g'), ('t', 't', 'b'), ..., ('y', 'y', 'y')]
I would like the list to look like this: 我希望列表看起来像这样:
['ttt','ttg','ttb','tty','tgt',...,'yyy']
How can I do that? 我怎样才能做到这一点?
Also, if I ever have a list of tuples like 'prd' how do I chain only the elements that are in each tuple. 另外,如果我有像“ prd”这样的元组列表,我如何只链接每个元组中的元素。
EDIT 编辑
I didn't want these types of outcomes: 我不想要这些类型的结果:
x = ['t','t','t','t','t','g','t','t','b','t','t','y',...,'y','y','y']
x = ['tttttgttbttytgt...yyy']
Simply join them like this 像这样简单地加入他们
bS = 'tgby'
prd = ["".join(it) for it in itertools.product(bS, repeat=len(bS)-1)]
Edit: A faster version, suggested by @alko in the comments 编辑:一个更快的版本,由@alko在评论中建议
prd = map(''.join, itertools.product(bS, repeat=len(bS)-1))
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