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无法修改/操纵来自动态PHP表单的Ajax / JSON响应中的动态内容

[英]Cannot Modify/Manipulate Dynamic Content From Ajax/JSON Response for A Dynamic PHP Form

I need a dynamic form which is supposed to work like this: 我需要一个动态的表单,它应该像这样工作:

  1. When user press "ADD" button, appear a new ..<.div> DOM to select a package. 当用户按下“ ADD”按钮时,出现一个新的.. <。div> DOM以选择一个程序包。
  2. Depending on the package, the row must change color (by adding/removing some classes). 根据包装的不同,该行必须更改颜色(通过添加/删除某些类)。

But I can't get it working. 但是我无法正常工作。 Here is my HTML: 这是我的HTML:

<button onclick='addDay();'>
<div class='content'>
</div>

My Javascript: 我的Javascript:

//FUNCTION 1: LOAD AJAX CONTENT
function addDay()
{
    baseUrl = $('input#helper-base-url').val();

    //Set caching to false
    $.ajaxSetup ({
        cache: true
    });

    //Set loading image and input, show loading bar
    var ajaxLoad = "<div class='loading'><img src='"+baseUrl+"assets/images/loading.gif' alt='Loading...'  /></div>";
    var jsonUrl = baseUrl+"car/add_day/"+count;
    $("div#loading").html(ajaxLoad);
    $("div#content").hide();
    $.getJSON(
        jsonUrl,
        {},
        function(json)
        {
                temp = "";

            if(json.success==true)
            {
                temp = json.content;
            }

            //Display the result
            $("div#content").show();
            $("div#content").html($("div#content").html()+temp);
            $("div#loading").hide();
          });
}

//FUNCTION 2: MODIFY AJAX CONTENT
$("#content").on("change", "select.switch", function (e) {

e.preventDefault();

//Get which row is to be changed in background's color
id = this.id;
id = id.substr(6);

//Add class "package1" which change row's background color
row = "row"+id;
row.addClass('package1');

}); });

My PHP 我的PHP

function add_day($count)
{
    $temp = "<div class='row".$count."'>
        <select id='switch".$count."' class='switch'>
        <option value='1'>Package 1</option>
        <option value='2'>Package 2</option>
        </select>
    </div>";

    $result = array(
        'success' => true,
        'content' => $temp,
        );

    $json = json_encode($result);
    echo $json;
}

PS. PS。 The form is not as simple as this but to make the problem solving easier, I remove the details. 表单并非如此简单,但是为了使问题解决更加容易,我删除了细节。 But I can't seem to change the class on the fly. 但我似乎无法即时更改课程。 Do we have a solution or a good work around here? 在这附近,我们有解决方案还是好的工作?

Edit 1: Sorry I didn't make myself clear before. 编辑1:对不起,我之前并没有明确表态。 I had no problem with getting the id or variable (it was okay, when I alert it the right value comes out - but after I add the class, no color changes is seen). 我获取ID或变量没有问题(没关系,当我警告它时会显示正确的值-但添加类后,看不到颜色变化)。 I run it: 我运行它:

a. 一种。 On button click, load Ajax content. 单击按钮后,加载Ajax内容。

b. b。 Ajax content (which results contains a ) loaded successfully. Ajax内容(结果包含)已成功加载。

c. C。 FAIL: On change, add class "package1" to the div row. 失败:更改后,将类“ package1”添加到div行。 (So, I had no problem with getting the right id or class name. When I alert the variables it gives the right result, BUT the color doesn't change. I can't check whether class is successfully added or not.) (因此,获取正确的ID或类名没有问题。当我警告变量给出正确的结果时,颜色不会改变。我无法检查类是否已成功添加。)

$("#content").on("change", "select.switch", function (e) {
    e.preventDefault();

    $('.row' + $(this).attr('id').replace('switch', '')).addClass('package1');
});

Assuming that everything else is ok 假设其他一切都OK

//Get which row is to be changed in background's color
id = this.id;
id = id.substr(6);

//Add class "package1" which change row's background color
row = "row"+id;
row.addClass('package1');

This is the problem. 这就是问题。 To get the attibute id you have to do 要获得礼节身份证,您必须做

var id = $(this).attr('id').substr(6);

You have to use $(this) and not this by the way to use all of jQuery functionalities. 您必须使用$(this)而不是this来使用所有jQuery功能。

Same below 下同

$(row).addClass('package1');

So, full code: 因此,完整代码:

//Get which row is to be changed in background's color
var id = $(this).attr('id').substr(6);

//Add class "package1" which change row's background color
$('.row'+id).addClass('package1');

Changing the class to id solved the problem (using #row0 instead of .row0). 将类更改为id可解决问题(使用#row0而不是.row0)。 Sorry and thank you for your time :) 对不起,谢谢您的时间:)

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