获取Android设备的所有者名称

Question

The following code works on an emulator, but fails to run on Samsung Galaxy S III.

    final String[] projection = new String[]
    { ContactsContract.Profile.DISPLAY_NAME };
    String name = null;
    final Uri dataUri = Uri.withAppendedPath(ContactsContract.Profile.CONTENT_URI, ContactsContract.Contacts.Data.CONTENT_DIRECTORY);
    final ContentResolver contentResolver = getContentResolver();
    final Cursor c = contentResolver.query(dataUri, projection, null, null, null);

    try
    {
        if (c.moveToFirst())
        {
            name = c.getString(c.getColumnIndex(ContactsContract.Profile.DISPLAY_NAME));
        }
    }
    finally
    {
        c.close();
    }
    System.out.println(name);

Here is the exception:

12-03 20:57:15.751: E/AndroidRuntime(28172): FATAL EXCEPTION: main
12-03 20:57:15.751: E/AndroidRuntime(28172): java.lang.RuntimeException: Unable to start activity ComponentInfo{ht.smca.flashligh/ht.smca.flashligh.MainActivity}: java.lang.NullPointerException
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2100)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2125)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.access$600(ActivityThread.java:140)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1227)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.os.Handler.dispatchMessage(Handler.java:99)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.os.Looper.loop(Looper.java:137)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.main(ActivityThread.java:4898)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at java.lang.reflect.Method.invokeNative(Native Method)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at java.lang.reflect.Method.invoke(Method.java:511)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1006)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:773)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at dalvik.system.NativeStart.main(Native Method)
12-03 20:57:15.751: E/AndroidRuntime(28172): Caused by: java.lang.NullPointerException
12-03 20:57:15.751: E/AndroidRuntime(28172):    at com.android.internal.os.LoggingPrintStream.println(LoggingPrintStream.java:298)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at ht.smca.flashligh.MainActivity.onCreate(MainActivity.java:68)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.Activity.performCreate(Activity.java:5206)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1083)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2064)
12-03 20:57:15.751: E/AndroidRuntime(28172):    ... 11 more

Any Suggestions? I do this for learning purposes, ie for a seminar.

Answer 1

This will help you get the owner name stored on the device:

Cursor c = getApplication().getContentResolver().query(ContactsContract.Profile.CONTENT_URI, null, null, null, null); 
c.moveToFirst();
textView.setText(c.getString(c.getColumnIndex("display_name")));
c.close();

Make sure you add this permission in the manifest:

<uses-permission android:name="android.permission.READ_CONTACTS"/>

Answer 2

You have java null pointer exception so name is null. Put your system.out.println() in the try and you won't have this error. After for getting the name I don't really know – Clad

Not my post but your answer : Get Android Device Name (for android device model my bad)

 android.os.Build.MODEL;

Here are two ways to do it :

How can I get the google username on Android?

How can I get the first name (or full name) of the user of the phone?

Answer 3

ContentResolver cr=getContentResolver();
Cursor curser = cr.query(ContactsContract.Profile.CONTENT_URI, null, null, null, null);
if(curser.getCount()>0){
    c.moveToFirst();
    String name=curser.getString(curser.getColumnIndex(
        ContactsContract.Profile.DISPLAY_NAME));
    Toast.makeText(MainActivity.this, "name"+name, Toast.LENGTH_SHORT).show();
}
c.close();

Answer 4

This code will give owner full information

Try this code:

public class EmailFetcher{

    static String getName(Context context) {
        Cursor CR = null;
        CR = getOwner(context);
        String id = "", name = "";
        while (CR.moveToNext())
        {
            name = CR.getString(CR.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
        }
        return name;
    }


    static String getEmailId(Context context) {
        Cursor CR = null;
        CR = getOwner(context);
        String id = "", email = "";
        while (CR.moveToNext()) {
            id = CR.getString(CR.getColumnIndex(ContactsContract.CommonDataKinds.Email.CONTACT_ID));
            email = CR.getString(CR.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
        }
        return email;
    }


    static Cursor getOwner(Context context) {
        String accountName = null;
        Cursor emailCur = null;
        AccountManager accountManager = AccountManager.get(context);
        Account[] accounts = accountManager.getAccountsByType("com.google");
        if (accounts[0].name != null) {
            accountName = accounts[0].name;
            String where = ContactsContract.CommonDataKinds.Email.DATA + " = ?";
            ArrayList<String> what = new ArrayList<String>();
            what.add(accountName);
            Log.v("Got account", "Account " + accountName);
            for (int i = 1; i < accounts.length; i++) {
                where += " or " + ContactsContract.CommonDataKinds.Email.DATA + " = ?";
                what.add(accounts[i].name);
                Log.v("Got account", "Account " + accounts[i].name);
            }
            String[] whatarr = (String[])what.toArray(new String[what.size()]);
            ContentResolver cr = context.getContentResolver();
            emailCur = cr.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, null, where, whatarr, null);
            if (id != null) {
                // get the phone number
                Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[]{id}, null);
                while (pCur.moveToNext())
                {
                    phone = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                    Log.v("Got contacts", "phone" + phone);
                }
                pCur.close();
            }
        }
        return emailCur;
    }
}

Answer 5

ContentResolver cr=getContentResolver();
Cursor curser = cr.query(ContactsContract.Profile.CONTENT_URI, null, null, null, null);
if(curser.getCount()>0){
    c.moveToFirst();
    String name=curser.getString(curser.getColumnIndex(
        ContactsContract.Profile.DISPLAY_NAME));
    Toast.makeText(MainActivity.this, "name"+name, Toast.LENGTH_SHORT).show();
}
c.close();

Use the above code for fetching owners name from android device. This basically fetches the name stored in contacts for me user.

Note : There will be an exception like the below for few users

android.database.CursorIndexOutOfBoundsException: Index 0 requested, with a size of 0 at android.database.AbstractCursor.checkPosition(AbstractCursor.java:460) at android.database.AbstractWindowedCursor.checkPosition(AbstractWindowedCursor.java:136) at android.database.AbstractWindowedCursor.getString(AbstractWindowedCursor.java:50) at android.database.CursorWrapper.getString(CursorWrapper.java:137)

This exception is not phone specific or user specific. Some users do not set their own contact in the contact list. So for resolving this the user on which the app is started needs to setup in Contacts application the first line that is ME contact. Just enter your name in personal info and card will be generated.

@Leejjon ^^