在C中将一个数组的元素复制到另一个

Question

So I am trying to use char array in C to copy from one array to another, each element at a time, however, I am stuck at this part. I did try to research but may be I'm a dumb or what not, I still could not get it right. Here is my code:

Say I have two array

char arr1[1000][3]
char arr2[1000][3]

So wHat I mean is that [3] equal length of the string and each array has 1000 elements. So arr1[0] = "AB\\0"

I can't, obviously, do arr1[i] = arr2[i]; won't work of course, I did try strcpy but don't quite get it right. Please help me out a bit, thank you :)

Here a portion of it, the specific function I writing: Please just answer the one I ask, I can do this easily in Java but I really learning C so... An example would be nice :D

//build stacks                                                                                                                                                                                                     
card_pos_ptr add_card(card_pos_ptr head, char card_list[1000][3], int index){
  int i,k = 0;
  int start_index = index;
  card_pos_ptr current = head;
  for(i=0;i<13;i++){
    for(k=0;k<4;k++){
      if(current->card_stack == NULL){
        card_ptr node = (card_ptr)malloc(sizeof(card));
    strcpy(node->card_name,);
        node->up = false;
        node->down = NULL;
        start_index++;
      }else{
        card_ptr node = (card_ptr)malloc(sizeof(card));
        //node->card_name[0] = card_list[start_index];                                                                                                                                                             
        node->up = false;
        node->down = current->card_stack;
        current->card_stack = node;
        start_index++;
      }
    }
    current = current->next_pos;
  }

}

Answer 1

Not sure what you are trying to do with this declaration but in frist place to declare array you need something like :

  char arr1[1000][3];
  char arr1[0][0] = 'A';
  char arr1[0][0] = 'B';
  ...

And in order to copy each element one at a time use a for loop:

if ( something that determines X ? ) {
    for ( int i=0; i < 3 ; i++ ) {
       arr2[x][i] = arr1[x][i];
    }
}

Answer 2

I would do it like this:

int i;
char arr1[1000][3];
char arr2[1000][3];

arr1[0][0]='v';

for(i=0;i<1000;++i)
{
    strncpy(arr2[i],arr1[i],3); //safe copy, copies max. 3 chars.
}

printf("%c\n",arr2[0][0]);

Answer 3

Try

memcpy( &node->card_name[0] ,card_list[start_index])