在Python的子流程模块中运行程序，并从Terminal中获取所需文件

Question

Is it feasible to run a program in Python's subprocess module, but with files from Terminal?

So I want to run the following program from within Python:

myProgram -a myArg

However, suppose that the above program requires the file myFile in the current directory, and it doesn't take the required file as an argument. So, if you run the above program in the directory where there is myFile , the program succeeds in processing. However, if you run it in the directory where there is NOT myFile , the execution fails.

And when I tried to execute the program from within Python's subprocess.Popen() , with shell=True , the program doesn't work and it looks like the reason it failed is the program wasn't able to read myFile when executed from within Python.

So, is there any way to run it successfully from within Python?

Answer 1

subprocess.Popen('myProgram -a myArg', cwd='/folder/with_myFile/')

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