如何从php表单获取变化的属性的值？

Question

I am pulling information to be displayed from my database and what id like to happen is when the user clicks on a selection, its takes them to a form that would be just for that selection. So i have one form and im trying to pull the name attribute whose value is set but $form_id which gets its value depending on the person chosen. on the top id get the attribute's value displayed in my url bar which i dont mind, but i cant seem to echo it out. After I am able to pull the value i will then place it back into the database. Please see code below. Thank you!

EDIT: For further clarification, i am pulling a list of names and ID's from the database. I am also pulling just the ID a second time and assigning it to form_id. I display this information on a button because when you click that button it should take you to a form that will then ask you for information that will be added to the row that holds your form_id. My problem is that form_id isnt coming over as the variable but what its assigned to ex. if form id assumes the value of 7, as per the id it pulls from the database, a $_GET(['form_id']) no longer works because 7 is what is being sent over, not form_id

Before you submit form (click button):

<?php
while($pro_showcase = mysqli_fetch_assoc($pro_s))
{
    $form_id = $pro_showcase['performance_id'];
    echo "<div class=\"xs-col-4 col-sm-offset-2 separate\"><form 
        role=\"form\"action=\"judge-form.php\" method=\"get\"><button name=\"$form_id\"  
        type=\"submit\" class=\"btn btn-danger\">        <p>ID: ";
    echo implode("<br> ",$pro_showcase);

    echo "</p></button></form></div>";
}
?>

After submission, where it submits to:

<?php
if (isset($_GET['submit']))
{
    $n = $_GET["$form_id"];
    echo $n;
}
?>

Answer 1

You got the $form_id mixed up. The value in your HTML code will be replaced with whatever is in $form_id variable, but you won't have a $form_id array key in $_GET after you submit the form. This is because the names of the HTML form elements map to keys in $_GET . What you have done in your code is: map the value of $form_id variable (for example 7 ) to a key in the $_GET .

You should instead use constant name for the HTML form elment, but with value of the $form_id variable:

<button name="form_id" value=\"$form_id\" type=\"submit\" class=\"btn btn-danger\">

Then you can capture the value like this:

$n = $_GET['form_id'];

(without $ sign).

If you are confused with parsing variables into strings, you can use the curly syntax , which makes the string a lot more readable.