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返回的不是全部,而是仅返回每个联接表项的第一项

[英]Return not all, but only first item of each joined table item

SELECT Id
FROM Container_A 
JOIN Container_B 
ON 
Container_A.Container_B_FK = Container_B.Id
ORDER BY Container_A.Id

This query return all elements of all Container_A items related to Container_B. 该查询返回与Container_B相关的所有Container_A项的所有元素。 The question is - How to get only first (with min Id) item related to each Container_B item. 问题是-如何仅获取与每个Container_B项目相关的第一个(带有最小ID)项目。

    SELECT top 1 *,min(Id) as minimum
    FROM Container_A 
    JOIN Container_B 
    ON 
    Container_A.Container_B_FK = Container_B.Id
group by Container_A.id,Container_B.id 
    ORDER BY minimum 
SELECT 
    MIN(a.Id) AS a_id,
    b.Id AS b_id
FROM Container_A a
JOIN Container_B b
ON (Container_A.Container_B_FK = Container_B.Id)
GROUP BY b.Id
ORDER BY a_Id
SELECT Id
FROM Container_A 
 JOIN Container_B 
   ON Container_A.Container_B_FK = Container_B.Id
 ORDER BY Container_A.Id ASC
 LIMIT 0,1

The problem with queries like this is that "first" has no meaning at all unless you specify what the order of the items are within the group. 此类查询的问题在于,除非您指定项目在组中的顺序,否则“第一”根本没有任何意义。 If you want the lowest item id, then you can group on the container b and use the min aggreagate to get the lowest item id from each group: 如果您想要最低的项目ID,则可以在容器b上进行分组,并使用min aggreagate从每个组中获取最低的项目ID:

select
  b.Id,
  min(a.Id) as A_Id
from
  Container_B b
  inner join Container_A a on a.Container_B_FK = b.Id
group by
  b.Id
order by
  b.Id

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