如何以struct作为函数参考？

Question

I have the following struct:

struct pole{
    int sifra;              // sifra na artiklot
    string opis;            // opis na artiklot
    float cena;             // edinecna cena
    int vlez_kol;           // vlezna kolicina
    int izlez_kol;          // izlezna kolicina
    float dan_stapka;       // danocna stapka
    float iznos;            // iznos
    int datum;              // datum na vlez i izlez (GGMMDD)
};                          // maksimalen broj na artikli e 100

pole artikli[100];


void vlez_artikl(artikli[]){ // how to take the struct as reference?

}

And I'm writing a function to input elements for each element in the struct, but I don't know how to take the struct (by struct I mean the pole artikli[100] as a reference to the function?

Answer 1

void vlez_artikl(pole &artikli){

}

//later you can call

vlez_artikl(artikli[32]);

Answer 2

I think you want to pass the array of structs? If not, then timrau's answer is appropriate.

To use a reference, you need to have the function know the exact type referred to, including the array dimension. This is only possible with a template:

template <size_t N>
void vlez_artikl(pole (artikli&)[N]) { // take the struct[] by reference
    ....
}

As using templates has downsides (a template instantiation per N, N must be known at compile time, the template implementation must be exposed to the translation unit using it), it's far more common to write functions that access an array using a pointer (often with the array size passed alongside). Both the following are equivalent....

void vlez_artikl(pole artikli[], size_t n) ...;
void vlez_artikl(pole* artikli, size_t n) ...;