没有调用Ajax回调。 如何解决这个问题？

Question

Again I am here for your suggestions. I have some AJAX call for running code from my editor which is a PHP online editor. (You guys can check in my site .)

I have some ajax call for send the data of editor and received output.

Problem: for loop not executed properly.

1. Below for loop program is executed successfully

    <?php for($i=10;$i>1;$i--){ echo "$i<br>"; } ?> 

2. While this for loop is not executed

    <?php for ($x=0; $x<=10; $x++) { echo "The number is: $x <br>"; } ?> 

When I run this through FireBug, I get a response saying that the for loop has become an infinite loop in case of second loop (above).

Now here is my AJAX callback:

$.ajax({
    type: 'GET',
    url: 'exec.php',
    data: code,
    success: function(data) 
    {
        alert(data);
        $(loader).addClass("hidden");
        var stdout = $(form).children('.stdout');
        if (data.search("Parse error")>0)
        {
            var str = data.replace("<b>Parse error</b>:  ","");
        $(stdout).html(str);
        $(stdout).removeClass('hidden');    
        }   
        else
        {
            $(stdout).html(data);
            $(stdout).removeClass('hidden');
        }   
    },
    error: function(req, status, err) {
        alert(status);
        alert(err);
    },
    dataType: 'JSONP'
});

I have re-implemented this editor locally and run it; In FireBug I am getting this error:

Error: jQuery110106354119750428449_1386321122498 was not called

here is my JSON callback code from the server:

echo $_GET['callback']."(".json_encode($script_output).");";

Please help me to tackle this error.

Answer 1

After some test's, i thing the problem are the ++ in the url, try to encode:

encodeURIComponent

as this worked for me:

for ($x=0; $x<=10; $x%2B%2B)
  {
  echo "The number is: $x <br>";
  }

...

+ = %2B

the server got this: ($x=0; $x<=10; $x ) so it is infinite loop, as $x stays 0

Answer 2

Replace your code with

<?php
$opstr = "";
for ($x=0; $x<=10; $x++)
 {
   $opstr .= "The number is: $x <br>";
 }
echo $opstr;
exit();
?> 

And try to execute your ajax call again.