[英]After successful ajax POST operation nothing happens in the database
I've checked for duplicates and none of them are strictly related to this problem. 我已经检查了重复项,没有一个与这个问题严格相关。
I have the following javascript code 我有以下javascript代码
var value = $.ajax({
type: "POST",
url: "bank.php",
data: {sum:money},
cache: false,
async: true
}).done(function() {
console.log( "success" );
}).fail(function() {
console.log( "error" );
});
and php in bank.php 和php在bank.php中
if(isset($_POST['sum']))
{
$money = mysql_real_escape_string($_POST['sum']);
$query = "UPDATE banks SET currency = 1 WHERE amount = '.$money.'";
$result = mysql_query($query);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
}
I receive in the browser console "success" for the ajax operation but nothing happens in the database. 我在浏览器控制台中收到Ajax操作的“成功”消息,但是数据库中没有任何反应。 Take note that "currency" is a tinyint(1) and amount is an int(10) [I'm using sql tables as you might have guessed]. 请注意,“ currency”是tinyint(1),amount是int(10)[正如您可能已经猜到的,我正在使用sql表]。 What am I doing wrong? 我究竟做错了什么? (bank.php also includes the header to link to my database, so that's not the problem because I tested others queries there). (bank.php还包括链接到我的数据库的标头,所以这不是问题,因为我在那里测试了其他查询)。
I believe the code isn't going through the if(isset($_POST['sum']))
validation but don't understand why. 我相信代码不会通过if(isset($_POST['sum']))
验证,但不明白为什么。 Any suggestions? 有什么建议么?
Try this : 尝试这个 :
$query = "UPDATE banks SET currency = 1 WHERE amount = ".$money.";
Hope this help u. 希望对您有帮助。
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