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PHP从mysql_ *迁移到mysqli_

[英]PHP Migrating from mysql_* to mysqli_

I just took up a old project and the first thing I needed to do was to migrate from the mysql_* extension to the mysqli_* one. 我只是承担了一个老项目,而我要做的第一件事是从mysql_*扩展名迁移到mysqli_*一个。 I haven't worked with PHP much before... Mosts of the new code works but in the examples below I seems to mess things up... 我之前还没有使用过PHP。大多数新代码都可以使用,但是在下面的示例中,我似乎把事情搞砸了...

Old function: 旧功能:

function user_id_from_username($username) {
    $username = sanitize($username);
    return mysql_result(mysql_query("SELECT `user_id` FROM `users` WHERE `username` = '$username'"), 0, 'user_id');
}

New(none working) function: 新增(无工作)功能:

function user_id_from_username($username) {
    $username = sanitize($username);
    $id = mysqli_query(connect(),"SELECT `user_id` FROM `users` WHERE `username` = '$username'");
    return $id;
}

Another old one: 另一个旧的:

function login($username, $password) {
    $user_id = user_id_from_username($username);

    $username = sanitize($username);
    $password = md5($password);

    return (mysql_result(mysql_query("SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username' AND `password` = '$password'"), 0) ==1) ? $user_id : FALSE;
}

And the new one: 和新的:

function login($username, $password) {
    $user_id = user_id_from_username($username);

    $username = sanitize($username);
    $password = md5($password);

    $check = mysqli_query(connect(),"SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username' AND `password` = '$password'");
    return $check == $user_id ? TRUE : FALSE;
}

My sanitize Function: 我的消毒功能:

function sanitize($data) {
    return htmlentities(strip_tags(mysqli_real_escape_string(connect(), $data)));
}

Ok, so in the first function you are trying to replace 好的,所以在第一个功能中,您尝试替换

return mysql_result(mysql_query("SELECT `user_id` FROM `users` WHERE `username` = '$username'"), 0, 'user_id');

Let's first make clear what this does: 首先让我们弄清楚它的作用:

  • specify query 指定查询
  • fetch the result 获取结果
  • get 0. row ("1st" in English) 得到0。行(英语中为“ 1st”)
  • get column user_id 获取列user_id

Now do this step-by-step with mysqli_ : 现在,使用mysqli_逐步进行mysqli_

//specify query
$result = mysqli_query(connect(),"SELECT `user_id` FROM `users` WHERE `username` = '$username'");
//fetch result
$row = mysqli_fetch_assoc($result);
//get column
return $row['user_id'];

You don't need to specify the row as fetch_assoc returns only one. 您无需指定该行,因为fetch_assoc仅返回一个。


Now for the second function 现在是第二个功能

return (mysql_result(mysql_query("SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username' AND `password` = '$password'"), 0) ==1) ? $user_id : FALSE;
  • specify query 指定查询
  • fetch result 取得结果
  • get 0. row 得到0。行
  • if this equals 1: return user_id , otherwise FALSE 如果等于1:返回user_id ,否则返回FALSE

Now with mysqli_ : 现在使用mysqli_

//specify query
$result = mysqli_query(connect(),"SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username' AND `password` = '$password'");
//fetch result
$row = mysqli_fetch_row($result);
//if first returned column is equal to 1 return $user_id
//otherwise FALSE
return ($row[0]==1) ? $user_id : FALSE;

But wait - why did I use mysqli_fetch_row here whereas mysqli_fetch_assoc was used above? 但等待-为什么我用mysqli_fetch_row这里,而mysqli_fetch_assoc上面使用? RTM ;) RTM;)


What have we learned today? 今天我们学到了什么? Only because you can write your code as short as possible doesn't mean you should. 仅因为您可以编写尽可能短的代码并不意味着您应该这样做。 If the original code had been split up a bit more, the transition to MySQLi should have been quite easy, as you could have easily debugged smaller parts instead of a complex expression. 如果对原始代码进行了更多拆分,则向MySQLi的过渡应该非常容易,因为您可以轻松调试较小的部分,而不是复杂的表达式。

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