如何使用反射使用一些参数调用未知的Rust函数？

Question

I'm having a lot of fun playing around with Rust having been a C# programmer for a long time but I have a question around reflection. Maybe I don't need reflection in this case but given that Rust is strongly typed I suspect I do (I would definitely need it in good ol' C#, bless its cotton socks).

I have this situation:

use std::collections::HashMap;

fn invoke_an_unknown_function(
    hashmap: HashMap<String, String>,
    // Something to denote a function I know nothing about goes here
) {
    // For each key in the hash map, assign the value
    // to the parameter argument whose name is the key
    // and then invoke the function
}

How would I do that? I'm guessing I need to pass in some sort of MethodInfo as the second argument to the function and then poke around with that to get the arguments whose name is the key in the hash map and assign the values but I had a look around for the reflection API and found the following pre-Rust 1.0 documentation:

• Module std::reflect
• Module std::repr
• [rust-dev] Reflection system

None of these give me enough to go on to get started. How would I implement the function I describe above?

Answer 1

Traits are the expected way to implement a fair amount of what reflection is (ab)used for elsewhere.

trait SomeInterface {
    fn exposed1(&self, a: &str) -> bool;
    fn exposed2(&self, b: i32) -> i32;
}

struct Implementation1 {
    value: i32,
    has_foo: bool,
}

impl SomeInterface for Implementation1 {
    fn exposed1(&self, _a: &str) -> bool {
        self.has_foo
    }

    fn exposed2(&self, b: i32) -> i32 {
        self.value * b
    }
}

fn test_interface(obj: &dyn SomeInterface) {
    println!("{}", obj.exposed2(3));
}

fn main() {
    let impl1 = Implementation1 {
        value: 1,
        has_foo: false,
    };
    test_interface(&impl1);
}