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使用push_back时std :: unique_ptr是否已移入std :: vector?

[英]Is a std::unique_ptr moved into a std::vector when using push_back?

I have a question about how a std::unique_ptr is inserted into a std::vector . 我有一个关于如何将std::unique_ptr插入std::vector Imagine I have a function that produces objects as follows: 想象一下,我有一个生成对象的函数,如下所示:

std::unique_ptr<CObject> createObjects()
{
    return std::unique_ptr<CObject> (new CObject());
}

Now in my code, I have a std::vector<std::unique_ptr<CObjects>> vec and I insert elements like so: 现在在我的代码中,我有一个std::vector<std::unique_ptr<CObjects>> vec ,我插入的元素如下:

vec.push_back(createObjects());

Now my question is: Is the unique_ptr moved into the vector or is it copied? 现在我的问题是: unique_ptr移入向量还是被复制?

A unique_ptr cannot be copy-constructed or copy-assigned. unique_ptr不能复制构造或复制分配。 In the case of a push_back into a vector, it is moved, provided it is an rvalue . push_back进入向量的情况下,只要它是一个rvalue就会被移动。 To test this, you can try pushing an lvalue . 要测试这个,你可以尝试推左值 This would require the unique_ptr to be copyable or assignable, and so would fail: 这将要求unique_ptr可复制或可分配,因此会失败:

std::unique_ptr<CObject> p(new CObject());
std::vector<std::unique_ptr<CObject>> vec;
vec.push_back(p); // error!
vec.push_back(std::unique_ptr<CObject>(new CObject())); // OK
vec.push_back(std::move(p)); // OK

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