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计算多个列中给定条件的唯一出现次数

[英]Count unique occurrences of a given criteria across multiple columns

原文 2013-12-10 22:44:09 2 1 arrays/ sum/ match/ vlookup

I have 3 columns that I need to count the number of unique occurrences of a particular value between the 3 columns and return the number of occurrences in a corresponding column. 我有3列，我需要计算3列之间特定值的唯一出现次数，并返回对应列中出现的次数。

Column A contains account #'s that will have the same # appear multiple times. 列A包含将多次出现相同编号的帐户＃。 Column B is a rating # (1-3 with all #'s appearing multiple times for each account # in column A). B列是等级＃（A列中每个帐户＃的所有号码都出现＃1-3）。 Column C is an account name that will always be the same for each account # (Column A). C列是一个帐户名称，每个帐户编号（A列）始终相同。 Column D needs to show the total number of defective account numbers (column A) per account name (column C). D列需要显示每个帐户名称（C列）的有缺陷的帐户总数（A列）。 An account # is defective if it had a rating of 3, no matter how many times the 3 appeared. 如果帐户＃3的评分为3，则该帐户＃有缺陷，无论该帐户出现3次。

I will need the data in column D for my pivot table. 我将需要数据透视表的D列中的数据。

Below is an array formula that I'm using now and it works sort of; 下面是我现在正在使用的数组公式，它在某种程度上起作用； however, it only returns the number of defective cases for an acct name on a row where the rating is 3. Otherwise, it returns a value of 1. If the acct # has a value of 3 on ANY row, I need the number of total defective acct #'s for the corresponding acct name to appear in column D. 但是，它只返回评级为3的行中acct名称的有缺陷案例数。否则，它返回值1。如果acct＃在ANY行中的值为3，我需要相应帐户名称的总缺陷帐户编号出现在D列中。

{=SUM(IF(FREQUENCY(IF(E5=3,IF(R$5:R$300=R5,MATCH(A$5:A$300,A$5:A$300,MATCH(E$5:E$300,E$5:E$300,0)*0)),0),ROW(R$5:R$300)-ROW(R$5)+1),1))} {= SUM（IF（FREQUENCY（IF（E5 = 3，IF（R $ 5：R $ 300 = R5，MATCH（A $ 5：A $ 300，A $ 5：A $ 300，MATCH（E $ 5：E $ 300，E $ 5：E $ 300,0）* 0）），0），ROW（R $ 5：R $ 300）-ROW（R $ 5）+1），1））}

1 个解决方案

If you can, please try =COUNTIFS(B:B,3,A:A,A5) in D5 copied down to suit. 如果可以，请尝试将=COUNTIFS(B:B,3,A:A,A5)复制下来以适合您。 If not possible, please advise which software and version is relevant. 如果无法解决，请告知相关的软件和版本。