在ArrayList中查找特定单词

Question

I am writing a code that loads an ArrayList of Strings and checks to see if a specific word is used. This may sound weird but the specifics are:

Number of toots containing "toot" (with any capitalization and allowing zero (0) in place of oh (o), eg, "to0t" should be counted too); however, you should not count a toot if it only contains "toot" as part of another work, eg, "tooter" is not enough to count a toot.

I have tried many things but it still doesn't seem to work and count the proper results.

Here is what I have now after some help from members:

for (String toot : toots) {
        toot = toot.toLowerCase().replace("0", "o").trim();
        if(toot.equalsIgnoreCase("toot")){
           tootsWithToot++;
        }
}

An example would be with the "toot messages" (each line is a separate message):

**1 toot 2 t00t

toot

will be back

tooter tooting**

The results should show 2 as tooter and tooting aren't the word "toot" with the O or 0 variations.

I think a change should be that I need .contains but I'm not 100% sure. Again, I apologize for this humorous request, I am still a novice programmer.

Answer 1

The following should match your requirements. It uses regex to match obnly "whole word" occurrences of your string.

for (String toot : toots) {
    toot = toot.toLowerCase().replace("0", "o").trim();
    toot = toot.toLowerCase().replace("O", "o").trim();
    toot = toot.toLowerCase().replace("T", "t").trim();
    if(toot.matches(".*\\btoot\\b.*")){
        tootsWithToot++;
    }
}

A more pure regex example would be something like the following:

for (String toot : toots) {
    if(toot.matches(".*\\b[tT][oO0]{2}[tT]\\b.*")){
        tootsWithToot++;
    }
}

This regex matches instances of toot , ignoring the case of the t's [tT] and the o's (whilst also including 0) [oO0] , when they are surrounded by any word break character.