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如何在linux shell脚本中计算日期-N?

[英]How to calculate date -N in linux shell scripting?

I want to know how to calculate date-n where date is systems current date and N is number of days i want to add or subtract. 我想知道如何计算date-n,其中date是系统当前日期,N是我想要添加或减去的天数。

I am able to do get yesterday's date but dont know how to add or subtract no of days to get desired date : 我能够做到昨天的日期,但不知道如何增加或减去没有天数来获得所需的日期:

date_dir=`date +%Y-%m-%d -d yesterday`
echo "$date_dir"

Thanks 谢谢

You can supply an argument '-N days' to the -d option: 您可以为-d选项提供参数'-N days'

$ date +%Y-%m-%d -d '-42 days'     # This would subtract 42 days from the current date
2013-10-30
$ date +%Y-%m-%d -d '+42 days'     # This would add 42 days to the current date
2014-01-22

and assign the result to a variable: 并将结果分配给变量:

$ date_dir=$(date +%Y-%m-%d -d '-42 days')
$ echo $date_dir 
2013-10-30
var=`date +%s`;

date=`date --date=@$var +%Y-%m-%d`

echo $date

you can add/subtract no of days you need. 您可以添加/减去您需要的日期。 just remember it is in seconds 只记得它是在几秒钟内

From man pages: 从手册页:

%s seconds since 1970-01-01 00:00:00 UTC 自1970-01-01 00:00:00 UTC以来的%s秒

Convert seconds since the epoch (1970-01-01 UTC) to a date 将纪元(1970-01-01 UTC)之后的秒数转换为日期

$ date --date='@2147483647' $ date --date ='@ 2147483647'

edit: devNull provided better answer 编辑:devNull提供了更好的答案

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