没有可见的@interface声明选择器

Question

I have a SSLYFoodDetailViewController.h whose contents are

#import <UIKit/UIKit.h>

@interface SSLYFoodDetailViewController : UIViewController

@property(nonatomic, weak) NSString *foodItem;
@property(nonatomic, weak) NSString *restaurantName;

- (void) setFoodItem:(NSString *)foodItem;
- (void) setRestaurantName:(NSString *)restaurantName;

@end

In another file SSLYTableViewController.m inside the prepareForSegue method, I try to do the following -

SSLYFoodDetailViewController *sslyFoodDetailViewController = [segue destinationViewController];
[sslyFoodDetailViewController setFoodItem:@"Pasta"];

XCode is giving me an error that there is No visible @interface for 'SSLYFoodDetailViewController' declares the selector 'setFoodItem' .

At the top of the SSLYTableViewController.m , I have the import statement -

#import "SSLYFoodDetailViewController.h"

What is it that I am missing?

Answer 1

That doesn't make any sense, except that setFoodItem: is implied by the foodItem @property declaration.

Try removing the declarations for setFoodItem: and setRestaurantName: in your header - that definitely won't hurt anything because they're redundant.

If that doesn't work, try the property accessor notation:

sslyFoodDetailViewController.foodItem = @"Pasta";

Also of note, you're probably getting a warning on the line:

SSLYFoodDetailViewController *sslyFoodDetailViewController = [segue destinationViewController];

You should add an explicit cast in that line, as follows:

SSLYFoodDetailViewController *sslyFoodDetailViewController = (SSLYFoodDetailViewController *) [segue destinationViewController];