[英]Dynamically applied filter on (self-referential) relationship
I have a model that I would like to query with a filter. 我有一个要使用过滤器查询的模型。 I also want this filter to be applied on its children (one-to-many self-referential relationship).
我还希望将此过滤器应用于其子级(一对多的自我参照关系)。 Example:
例:
class Item(Model):
__tablename__ = 'item'
id = Column(Integer, primary_key=True)
color = Column(String)
parent_id = Column(Integer, ForeignKey('item.id'))
children = relationship(
'Item',
backref=backref('parent', remote_side=[id]),
lazy='dynamic'
)
item = session.query(Item).filter(Item.color == 'blue').one()
Now I want to apply the same filter on the children
collection once, and be able to access the filtered collection in a transparent way later. 现在,我想一次
children
集合应用相同的过滤器,并在以后能够以透明方式访问过滤后的集合。
I could imagine something like: 我可以想象像这样的东西:
item.children.apply_filter(Item.color == 'blue') # `children` is dynamic
and then accessing item.children
would be equivalent to accessing item.children.filter(Item.color == 'blue').all()
now. 然后访问
item.children
等同于立即访问item.children.filter(Item.color == 'blue').all()
。 Note that with this solution, the fact that the relationship is self-referential doesn't matter. 请注意,使用此解决方案,关系是自引用的事实无关紧要。
SQLAlchemy's API is huge and I can't figure out if there is a proper way to do this (or something equivalent). SQLAlchemy的API很大,我不知道是否有适当的方法来执行此操作(或等效方法)。
(Is it possible to modify the primaryjoin
of a relationship at query time ? Or give it a parameter ?) (是否可以在查询时修改关系的主
primaryjoin
?或者给它一个参数?)
Please note that if you have multiple items with the same color, your original query item = session.query(Item).filter(Item.color == 'blue').one()
will fail. 请注意,如果您有多个具有相同颜色的项目,则原始查询
item = session.query(Item).filter(Item.color == 'blue').one()
将失败。
When you get past that and get your (parent) Item
instance: 当您通过该操作并获得(父)
Item
实例时:
my_item = session.query(Item).filter(Item.color == 'blue')[0]
# my_item = session.query(Item).filter(Item.color == 'blue').filter(Item.parent == None).one() # assume this is only one root item per color
because children
is dynamic
, my_item.children
will return you a query. 由于
children
是dynamic
,因此my_item.children
将向您返回查询。 In this case you simply apply another filter and you are done: 在这种情况下,您只需应用另一个过滤器即可完成:
my_blue_children = my_item.children.filter(Item.color == 'blue').all()
The filter
clause will now apply a filter to the select statement loading children. 现在,
filter
子句将对选择语句加载子级应用过滤器。
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