获取具有独立于元素级别的特定名称的所有标签

Question

I'm creating html with PHP (simpleXML), a XML-document and XSL.

Is there a way to replace all elements with a specific name (ie. ) with a html-tag (ie. ). I guess the answer is 'yes", but how do I do it?

With my code, the keyword-element must be the top child of the root-element for it to work.

The following don't work:

XML:

<document>
<chapter>This is the first chapter</chapter>
<text>This is a text, with a <keyword>keyword</keyword></text>
</document>

XSL:

    <xsl:template match="text">
            <xsl:value-of select="."/>
    </xsl:template>
<xsl:template match="*[starts-with(name(), 'keyword')]">
            <xsl:copy>
                <b>
                    <xsl:value-of select="."/>
                </b>
            </xsl:copy>
    </xsl:template>

The <keyword> -element can exist on all kinds of levels in the document, lets say even in the title. How can I then select it from the XSL? I guess there is something to do with the 'match'-attribute. I tried match="*/keyword" without any luck.

This code works when the <keyword> -element is the top child of the root, but won't work inside for example the <text> -element.

Answer 1

I have modified your input example to:

<document>
    <title>This is the <keyword>first</keyword> title</title>
    <chapter>This is the <keyword>second</keyword> chapter</chapter>
    <text>This is a text, with a <keyword>third</keyword> keyword in it.</text>
</document>

Using the following stylesheet:

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>

<!-- Identity Transform -->
<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

<!-- exception -->
<xsl:template match="keyword">
    <b><xsl:apply-templates/></b>
</xsl:template>

</xsl:stylesheet> 

you will get the following output:

<?xml version="1.0" encoding="utf-8"?>
<document>
    <title>This is the <b>first</b> title</title>
    <chapter>This is the <b>second</b> chapter</chapter>
    <text>This is a text, with a <b>third</b> keyword in it.</text>
</document>

Answer 2

I'm not total sure what you are trying to do, but the following query:

 <xsl:value-of select="//keyword/text()"/>

will select all <keyword> element's content regardless of their position in tree. This because I'm using the // in front of

Answer 3

I think what you are looking for is on this question .

Basically, the */keyword is looking for a string that has "/keyword" in it, and not the actual node.

If you try

    <xsl:template match="*[starts-with(name(), 'keyword')]">

You should be in good shape.