Django 1.5多用户身份验证或

Question

I created a Django 1.5 WebApp with custom User model. And it works. :)

I already had a second User2 model that another App was using. This second User2 model isn't a Django app so it was built with different criteria. And it is already in production with many users.

Now I have the need to give both User and User2 the possibility to log-in and do completely different things.

I'm thinking about one single Django App to manage everything because in both cases I need to use both models: when User is logged-in I need also some information about User2 and viceversa.

I don't see a way to merge User , User2 because they have completely different fields. Plus User2 has a ForeignKey that points to User .

After several trials I discovered that django supports only one AUTH_USER_MODEL . So now I don't know how to proceed.

I see the following alternatives:

• create an abstract User Model ( AbstractUser ) and then subclass User and User2 but I do not know how and if this will work

• create a completely new Django WebApp but this require a bigger (and maybe unnecessary) effort

• find another way to authenticate User2 , maybe writing my custom auth code

Do you see any other option? Which is the best?

Any help would be appreciated!

Answer 1

I'm not sure if I understand exactly your problem but if I did I think what you're looking for is a OneToOneField .

When I'm working on projects where the clients want customized users, one of the best solution is to create a new model with a OneToOneField pointing to the Django User like a Profile model. When you have an User object, you can do user.profile and you get the profile related with user (so you can do user.profile.any_profile_field ).

It goes also in the other way, if you have the object Profile you can access to the User object like profile.user and do also profile.user.first_name

So if it fits well with your issue as I think, you should change your model to be a OneToOneField to User like this:

class Profile(models.Model):
    user = models.OneToOneField(User)
    field1 = models.CharField....
    #     ...    ...     ...
    #      Your fields here