Javascript比较2个数组中的值

Question

What would be a shorter way to write :

if (array1[0] >= array2[0] && array1[1] >= array2[1] && ...) {
do something;
}

I tried creating a function but I was not able to make it work, I'm still quite new at this.

Answer 1

The most elegant way would be to use .every

The every() method tests whether all elements in the array pass the test implemented by the provided function.

if (array1.every(function(e,i){ return e>=array2[i];})) {
    do something;
}

Answer 2

var isGreater = true;
for (var i = 0; i < array1.length; i++)
{
    if (array1[i] < array2[i])
    {
        isGreater = false;
        break;
    }
}

if (isGreater)
{
    //do something
}

You loop your first array and replace the numbers by the looping variable (i)

Answer 3

This will return true if all elements of a are greater than all elements of b . It will return as early as possible rather than having to compare all of the elements.

function compare(a, b) {
  for (i = 0; i < a.length; i++) {
      if (a[i] < b[i]) { return false;}
  }
  return true
 }