使用自定义uri启动android应用

Question

I tried to launch my android application with a link into an email.

https://hostname.com/somethingAndParameter

My server redirect this link to:

myscheme://host

i tried this intent-filter but it doesn't work:

<intent-filter>
        <action android:name="android.intent.action.VIEW"/>
        <category android:name="android.intent.category.DEFAULT"/>
        <category android:name="android.intent.category.BROWSABLE"/>
        <data android:host="host" android:scheme="myscheme"/>
</intent-filter>

Answer 1

Since you are not understanding by way of comments, let's try an answer...

Change your <intent-filter> to:

<intent-filter>
        <action android:name="android.intent.action.VIEW"/>
        <category android:name="android.intent.category.DEFAULT"/>
        <category android:name="android.intent.category.BROWSABLE"/>
        <data
           android:scheme="https"
           android:host="hostname.com"
           android:path="/somethingAndParameter"/>
</intent-filter>

Now your https://hostname.com/somethingAndParameter URL works on:

• iOS, because you said that you have this working
• Web, because you said that you have this working
• Android, because now when a user taps on this link (in an email or whatever) on most Android devices, the user will get a chooser, allowing the user to choose your application to process the link