如何从php形式的单选按钮获取值并在另一个php中检查值

Question

when i select any radio button on this form in index.php ,the condition for the value in radio button is not validated for the correct answer 当我在index.php中选择此表单上的任何单选按钮时，单选按钮中值的条件未得到正确答案的验证

index.php 的index.php

<html>
<head>Aptitude Test</head>
<body>
<?php require_once 'config.php';?>
<?php $response=mysql_query("select * from questions");?>    
<form method='post' id='quiz_form' >
<?php while($result=mysql_fetch_array($response)){ ?>
<div id="question_<?php echo $result['id'];?>" class='questions'>
<h2 id="question_<?php echo $result['id'];?>">
<?php echo $result['id'].".".$result['question'];?>
</h2>
<div class='align'>
<input type="radio" value="1" id='radio1_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>' >
<label id='answer1_<?php echo $result['id'];?>' for='answer1_<?php echo $result['id'];?>'><?php echo $result['answer1'];?></label>
<br/>
<input type="radio" value="2" id='radio2_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>' >
<label id='answer2_<?php echo $result['id'];?>' for='answer2_<?php echo $result['id'];?>'><?php echo $result['answer2'];?></label>
<br/>
<input type="radio" value="3" id='radio3_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>' >
<label id='answer3_<?php echo $result['id'];?>' for='answer3_<?php echo $result['id'];?>'><?php echo $result['answer3'];?></label>
<br/>
<input type="radio" value="4" id='radio4_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>' >
<label id='answer4_<?php echo $result['id'];?>' for='answer4_<?php echo $result['id'];?>'><?php echo $result['answer4'];?></label>
<input type="radio" checked='checked' value="5" style='display:none' id='radio4_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>'>
</div>
<br/>
<input type="button" id='next<?php echo $result['id'];?>' value='Next!' name='question' class='butt'/>
</div>
<?php }?>
</form>
<div id='result'>
<img src='results.jpg' alt='Results'/>
<br/>
</div>

<div id="demo1" class="demo" style="text-align:center;font-size: 25px;">00:00:00</div>
<script src="jquery-1.9.1.min.js"></script>
<script src="watch.js"></script>
<script>
$(document).ready(function(){
$('#demo1').stopwatch().stopwatch('start');
var steps = $('form').find(".questions");
var count = steps.size();
steps.each(function(i){
    hider=i+2;
    if (i == 0) {   
        $("#question_" + hider).hide();
        createNextButton(i);
    }
    else if(count==i+1){
        var step=i + 1;
        //$("#next"+step).attr('type','submit');
        $("#next"+step).on('click',function(){

           submit();

        });
    }
    else{
        $("#question_" + hider).hide();
        createNextButton(i);
    }

});
function submit(){
     $.ajax({
                    type: "POST",
                    url: "ajax.php",
                    data: $('form').serialize(),
                    success: function(msg) {
                      $("#quiz_form,#demo1").addClass("hide");
                      $('#result').show();
                      $('#result').append(msg);
                    }
     });

}
function createNextButton(i){
    var step = i + 1;
    var step1 = i + 2;
    $('#next'+step).on('click',function(){
        $("#question_" + step).hide();
        $("#question_" + step1).show();
    });
}
setTimeout(function() {
      submit();
}, 50000);
});
</body>
</html>

This is ajax.php which gets the selected radio button answer to check the answer is right or wrong, but the thing is the right answer condition if($_POST[$i] == $row['answer']) fails to check and does not increment the value $right_answer++; 这是ajax.php，它获取选定的单选按钮答案以检查答案是对还是错，但是如果（$ _POST [$ i] == $ row ['answer']）无法检查，那么事情就是正确的答案条件并且不会增加值$ right_answer ++;

ajax.php ajax.php

 <?php require_once 'config.php';
 $query = "select id,question,answer from questions";
 $result=mysql_query($query) or die(mysql_error());
 $right_answer=0;
 $wrong_answer=0;
 $unanswered=0;
 $i=1;
 while($row=mysql_fetch_array($result))
{ 
    if($_POST[$i] == $row['answer'])
    {
        $right_answer++;
    }
    else if($_POST[$i]==5)
    {
        $unanswered++;
    }
    else
    {
        $wrong_answer++;
    }
    $i++;
 }
 echo "<div id='answer'>";
 echo " Right Answer  : <span class='highlight'>". $right_answer."</span><br>";

 echo " Wrong Answer  : <span class='highlight'>". $wrong_answer."</span><br>";

 echo " Unanswered Question  : <span class='highlight'>". $unanswered."</span><br>";
 echo "</div>";
?>

config.php file: config.php文件：

<?php
define('DB_HOST','localhost');
define('DB_NAME','Aptitude');
define('DB_USER','root');
define('DB_PASSWORD','');
$conn=mysql_connect(DB_HOST,DB_USER,DB_PASSWORD) or die("Failed to connect to MySQL: " . mysql_error());
$db=mysql_select_db(DB_NAME,$conn) or die("Failed to connect to MySQL: " . mysql_error());


?>

Please help me to solve this problem. 请帮我解决这个问题。 Thanks in advance. 提前致谢。

Answer 1

This is not a full answer, but it will get you a long way down the road to a solution. 这不是一个完整的答案，但是它将带您走很长一段路，找到解决方案。

You were missing a few elements to your solution, but the most important omission was the javascript/jQuery. 您在解决方案中缺少一些元素，但是最重要的遗漏是javascript / jQuery。

jQuery is a javascript library that makes writing javascript MUCH shorter, simpler and more logical. jQuery是一个JavaScript库，可让编写JavaScript的时间更短，更简单且更具逻辑性。 jQuery can do almost anything that javascript can -- but to use it you must reference the jQuery library in the <head> tags, as I have done. jQuery几乎可以完成javascript可以做的所有事情-但要使用它，您必须像我一样在<head>标记中引用jQuery库。

With jQuery you can trap each click of a NEXT button and figure out what question was clicked. 使用jQuery，您可以捕获每个NEXT按钮的单击，并找出单击了哪个问题。 Then, you can run an ajax procedure and get the correct answer for that question. 然后，您可以运行ajax过程并获得该问题的正确答案。

AJAX is a javascript/jQuery procedure that allows you to ask the server to look something up for you, and then send back an answer. AJAX是一种javascript / jQuery过程，可让您要求服务器为您查找内容，然后发送回答案。 You cannot use ajax without javascript, and it is tons simpler to use the $.ajax() methods from jQuery than to use the XMLHTTPRequest methods of pure javascript. 没有JavaScript就不能使用ajax，使用jQuery中的$ .ajax（）方法要比使用纯JavaScript的XMLHTTPRequest方法简单得多。

To re-create your situation, I created a database with 7 fields: 为了重新创建您的情况，我创建了一个包含7个字段的数据库：

id - INT - the question number id -INT-问题编号
question - VARCHAR - the question text question -VARCHAR-问题文本
answer - VARCHAR - the correct answer answer -VARCHAR-正确答案
answer1 - VARCHAR - multiple-choice answer #1 答案1- answer1选择题＃1
answer2 - VARCHAR - multiple-choice answer #2 答案2- answer2选择题＃2
answer3 - VARCHAR - multiple-choice answer #3 答案3- answer3选择题＃3
answer4 - VARCHAR - multiple-choice answer #4 答案4- answer4选择题＃4

FILE 1: 文件1：

<?php 
    include 'connect.php'; //login to your database
    $response=mysql_query("select * from questions");
?>
<html>
    <head>
        <script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
        <script>
            $(document).ready(function() {
                var ques, user_ans;
                $('[id^=next]').click(function() {
                    ques = $(this).attr('id').split('t')[1];
                    user_ans = $(this).parent().find('input:radio:checked').attr('id');
                    user_ans = user_ans.split('_')[0];
                    user_ans = user_ans.split('o')[1];

                    $.ajax({
                        type:'POST',
                        url: 'ajaxCheck.php',
                        data:'ques=' +ques+ '&ans='+user_ans,
                        success: function(data){
                            alert(data);
                            ques = data.split('|')[0];
                            ans = data.split('|')[1];
                            $('#correct_'+ques).val(ans);
                        }
                    }); //END ajax
                }); //END next button.click
            }); //END document.ready
        </script>
    </head>
    <body>
        <form method='post' id='quiz_form' >
            <?php while($result=mysql_fetch_array($response)){ ?>
                <div id="question_<?php echo $result['id'];?>" class='questions'>
                    <h2 id="question_<?php echo $result['id'];?>">
                        <?php echo $result['id'].".".$result['question'];?>
                    </h2>
                    <div class='align'>
                        <input type="radio" value="1" id='radio1_<?php echo $result['id'];?>' name="radio<?php echo $result['id'];?>" >
                        <label id='answer1_<?php echo $result['id'];?>' for='answer1_<?php echo $result['id'];?>'><?php echo $result['answer1'];?></label>
                        <br/>
                        <input type="radio" value="2" id='radio2_<?php echo $result['id'];?>' name="radio<?php echo $result['id'];?>" >
                        <label id='answer2_<?php echo $result['id'];?>' for='answer2_<?php echo $result['id'];?>'><?php echo $result['answer2'];?></label>
                        <br/>
                        <input type="radio" value="3" id='radio3_<?php echo $result['id'];?>' name='radio<?php echo $result['id'];?>' >
                        <label id='answer3_<?php echo $result['id'];?>' for='answer3_<?php echo $result['id'];?>'><?php echo $result['answer3'];?></label>
                        <br/>
                        <input type="radio" value="4" id='radio4_<?php echo $result['id'];?>' name='radio<?php echo $result['id'];?>' >
                        <label id='answer4_<?php echo $result['id'];?>' for='answer4_<?php echo $result['id'];?>'><?php echo $result['answer4'];?></label>
                        <input type="radio" checked='checked' value="5" style='display:none' id='radio4_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>'>
                        <br/>
                        <input type="text" disabled="disabled" id="correct_<?php echo $result['id'];?>" />
                    </div>
                    <br/>
                    <input type="button" id='next<?php echo $result['id'];?>' value='Next!' name='question' class='butt'/>
                </div>
            <?php }?>
        </form>
    </body>
</html>

FILE 2: ajaxCheck.php 文件2：ajaxCheck.php

$ques = $_POST['ques'];
$ans = $_POST['ans'];

$query = "select id,answer,answer1,answer2,answer3,answer4 from questions WHERE id='$ques'";
$result=mysql_query($query) or die(mysql_error());

$r = mysql_fetch_assoc($result);

//You need to send back the ques# so jQuery knows which question block to update.
$out = $ques . '|' . $r['answer'];

echo $out;

Answer 2

Can you try this, added name as name='myradio[]' 您能尝试一下吗，将名称添加为name='myradio[]'

HTML: HTML：

 <input type="radio" value="1" id='radio1_<?php echo $result['id'];?>' name='myradio[]' >

PHP PHP

<?php
   print_r($_POST[myradio]);

 ?>

Answer 3

since i don't know what was the condition being checked i just wrote a echo statement before the condition and then i came to know that it was checking the value of radio button and not its answer so what i did was i changed the correct answer field in the database to the correct answer's no 因为我不知道要检查的条件是什么，所以我只是在条件之前写了一个echo语句，然后我才知道它正在检查单选按钮的值，而不是其答案，所以我所做的是更改了正确答案数据库中的字段为正确答案为否

while($response=mysql_fetch_array($result))
{      
           echo $response['answer'];//this showed the answer
           echo $_POST["$i"];//this showed the radio button no of the answer clicked
          //so thats why the condition when wrong all the time and so i changed the answer filed to the right answer's radio button number and hence the condition went true
    if($response['answer']==$_POST["$i"])
    {
    $right_answer++;    
    }
    else if($_POST["$i"]==5)
    {   
        $unanswered++;
    }
    else
    {
        $wrong_answer++;
    }
    $i++;
}

如何从php形式的单选按钮获取值并在另一个php中检查值

问题描述

3 个解决方案

解决方案1
1 2013-12-13 19:13:39

解决方案2
0 2013-12-13 17:55:38

解决方案3
0 已采纳 2013-12-14 18:03:38

如何从php形式的单选按钮获取值并在另一个php中检查值

问题描述

3 个解决方案

解决方案1 1 2013-12-13 19:13:39

解决方案2 0 2013-12-13 17:55:38

解决方案3 0 已采纳 2013-12-14 18:03:38

解决方案1
1 2013-12-13 19:13:39

解决方案2
0 2013-12-13 17:55:38

解决方案3
0 已采纳 2013-12-14 18:03:38