[英]PHP - How can i keep my user logged in?
I'm using a function for login. 我正在使用登录功能。
But when i change the page from my website, i have to login again. 但是当我从我的网站更改页面时,我必须再次登录。
how can i keep my user logged in when i change my page? 当我更改页面时,如何让用户登录?
Here my code: 这是我的代码:
<?php
error_reporting(0);
if($_POST['login']=="") {
?>
<form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>" >
<label><a>Utilizador</a><input type="text" name="login" id="s-user"></label>
<label><a>Senha</a><input type="text" name="password" id="s-pass"></label>
<input type="submit" class="submit" value="Entrar">
</form>
<?php
}
else {
?>
<?php
include("classes/Utilizadores/Cliente.class.php");
if($_REQUEST['login']!="") {
if($_REQUEST['password']!="") {
$clientes = new Cliente();
if($clientes->verificarCliente($_REQUEST['login'], $_REQUEST['password'])) {
echo "<br>";
} else {
echo "<br><a>Login ou senha errados, caso não tenha, <a href='criarconta.php'> registre-se</a>, <a>ou</a> <a href='index.php'>volte a tentar.</a></a><br>";
}
$clientes->endCliente();
} else {
echo "ERRO: Deve introduzir a sua password...<br>";
}
} else {
echo "ERRO: Deve introduzir o seu login...<br>";
}
}
?>
My function code: 我的功能代码:
function verificarCliente($login, $password) {
$sql = "SELECT * FROM users WHERE login LIKE '$login' AND password LIKE '$password'";
if(($rs=$this->bd->executarSQL($sql))){
if(mysql_fetch_row($rs)==false) {
return false;
} else {
echo "<br><b> <a>Bem-Vindo <font size=2>" .mysql_result($rs,0,"login")."</font></b></a><br><br><br>";
return true;
}
}
else {
return false;
}
}
Use $_SESSION
Variables. 使用
$_SESSION
变量。 http://www.php.net/manual/en/reserved.variables.session.php . http://www.php.net/manual/en/reserved.variables.session.php 。 They help you store variables you can access them from any other part of the website.
它们可以帮助您存储可以从网站的任何其他部分访问它们的变量。
On login success: 登录成功时:
1) Query basic info like first name, last name, sex, birthday etc. 1)查询姓名,姓氏,性别,生日等基本信息。
2) Save them in variables such as $first_name, $last_name etc. 2)将它们保存在$ first_name,$ last_name等变量中。
3) Assign those variables to sessions like this: 3)将这些变量分配给这样的会话:
$first_name = $_SESSION['first_name'];
$birthday = $_SESSION['birthday'];
On logout, simply destroy the session with session_destroy(). 注销时,只需使用session_destroy()销毁会话。
So $_SESSION['first_name']
would be the first name of the user that can be manipulated from anywhere on the code. 因此
$_SESSION['first_name']
将是可以从代码上的任何位置操作的用户的第一个名称。
EDIT : I quoted php.net instead of W3 school because a lot of people don't seem to like it. 编辑 :我引用了php.net而不是W3学校,因为很多人似乎不喜欢它。
You are not saving the state of a user. 您没有保存用户的状态。 You should save the state of a user in a session and retrieve on the next page.
您应该在会话中保存用户的状态并在下一页上检索。
Please review http://www.w3schools.com/php/php_sessions.asp 请查看http://www.w3schools.com/php/php_sessions.asp
First off I would highly recommend not using the LIKE operator, use the = operator instead. 首先,我强烈建议不要使用LIKE运算符,而是使用=运算符。 Also I would recommend using parametrized quires.
我也建议使用参数化的quires。 Also I would recommend hashing your user's passwords, salting them is a very good idea too.
此外,我建议哈希用户的密码,盐渍它们也是一个非常好的主意。
Give these pages a read. 阅读这些页面。 There is good information here:
这里有很好的信息:
How can I prevent SQL injection in PHP? 如何在PHP中阻止SQL注入?
Secure hash and salt for PHP passwords 为PHP密码保护哈希和盐
crackstation.net supplies a free library for multiple languages and a good explanation. crackstation.net提供了一个免费的多语言库和一个很好的解释。
But you need to keep track of the logged in user: 但您需要跟踪登录用户:
function verificarCliente($login, $password) {
$sql = "SELECT * FROM users WHERE login = '$login' AND password = '$password'";
if(($rs=$this->bd->executarSQL($sql))){
if(mysql_fetch_row($rs)==false) {
return false;
} else {
session_start();
$the_username = // grab the username from your results set
$_SESSION['username'] = $the_username;
// put other things in the session if you like
echo "<br><b> <a>Bem-Vindo <font size=2>" .mysql_result($rs,0,"login")."</font></b></a><br><br><br>";
return true;
}
}
else {
return false;
}
}
Now on other pages that require a user to be logged in 现在在需要用户登录的其他页面上
session_start();
if (!isset($_SESSION['username']) || empty($_SESSION['username'])) {
// redirect to your login page
exit();
}
$username = $_SESSION['username'];
// serve the page normally.
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.