用于从嵌套组中选择/提取的Python正则表达式

Question

I am trying to process a string with CHAR(int) and NCHAR(int) to convert those instances with their ASCII counter-parts. An example would be something like this:

CHAR(124) + (SELECT TOP 1 CAST(name AS VARCHAR(8000)) FROM (SELECT TOP 1 colid, name FROM [Projects]..[syscolumns]
WHERE xtype=char(85)
AND id = OBJECT_ID(NCHAR(69)+NCHAR(78)+NCHAR(95)+NCHAR(69)+NCHAR(109)+NCHAR(112)+NCHAR(108))

Note that I don't want to do anything to VARCHAR(int), and just to the CHAR(int) and NCHAR(int) parts only. The above should translate to:

|(SELECT TOP 1 CAST(name AS VARCHAR(8000)) FROM (SELECT TOP 1 colid, name FROM [Projects]..[syscolumns] WHERE xtype=U AND id = OBJECT_ID(EN_Empl)

Note that any "+" on either side of CHAR(int) or NCHAR(int) should be removed. I tried the the following:

def conv(m):
    return chr(int(m.group(2)))

print re.sub(r'([\+ ]?n?char\((.*?)\)[\+ ]?)', conv, str, re.IGNORECASE)

where str =the raw string that must be processed.

Somehow, the VARCHAR(8000) is being picked up. If I tweak the regex, the "=" after xtype is going away, rather than just the space and the "+" on either side of a CHAR(int) or NCHAR(int) instance.

Hope someone can pull me out of this.

ADDITIONAL SAMPLE STRINGS:

String "char(124)+(Select Top 1 cast(name as varchar(8000)) from (Select Top 1 colid,name From [Projects]..[syscolumns] Where id = OBJECT_ID(NCHAR(69)+NCHAR(78)+NCHAR(95)+NCHAR(69)+NCHAR(109)+NCHAR(112)+NCHAR(108)))"

Regex: r'(\\bn?char\\((\\d+)\\)(?:\\s*\\+\\s*)?)'

Result: "|(Select Top 1 cast(name as varchar(8000)) from (Select Top 1 colid,name From [Projects]..[syscolumns] Where id = OBJECT_ID(ENCHAR(78)+NCHAR(95)+NCHAR(69)+NCHAR(109)+NCHAR(112)+NCHAR(108)))"

Answer 1

You have three issues:

1. You need to use flags=re.IGNORECASE and not just re.IGNORECASE in re.sub . That is a keyword argument.
2. You need to use \\b to find the word boundary.
3. You should not use str as a name since you will overwrite the built-in by the same name

This works:

import re

tgt='''\
CHAR(124) + (SELECT TOP 1 CAST(name AS VARCHAR(8000)) FROM (SELECT TOP 1 colid, name FROM [Projects]..[syscolumns]
WHERE xtype=char(85)
AND id = OBJECT_ID(NCHAR(69)+NCHAR(78)+NCHAR(95)+NCHAR(69)+NCHAR(109)+NCHAR(112)+NCHAR(108))'''

pat=r'(\bn?char\((\d+)\)(?:\s*\+\s*)?)'

def conv(m):
    return chr(int(m.group(2)))

print re.sub(pat, conv, tgt, flags=re.IGNORECASE)    

More completely:

import re

tgt='''\
CHAR(124) + (SELECT TOP 1 CAST(name AS VARCHAR(8000)) FROM (SELECT TOP 1 colid, name FROM [Projects]..[syscolumns]
WHERE xtype=char(85)
AND id = OBJECT_ID(NCHAR(69)+NCHAR(78)+NCHAR(95)+NCHAR(69)+NCHAR(109)+NCHAR(112)+NCHAR(108))'''

pat=r'(\bn?char\((\d+)\)(?:\s*\+\s*)?)'

def conv(m):
    return chr(int(m.group(2)))

print re.sub(r'''
              (                                 # group 1
              \b                                # word boundary
              n?char                            # nchar or char
              \(                                # literal left paren
              (\s*\d+\s*)                       # digits surrounded by spaces
              \)                                # literal right paren
              (?:\s*\+\s*)?                     # optionally followed by a concating '+' 
              )                                 '''
            , conv, tgt, flags=re.VERBOSE | re.IGNORECASE)   

Prints:

|(SELECT TOP 1 CAST(name AS VARCHAR(8000)) FROM (SELECT TOP 1 colid, name FROM [Projects]..[syscolumns]
WHERE xtype=U
AND id = OBJECT_ID(EN_Empl)

Answer 2

You can go a long way just by adding the word boundary ( \\b ) assertion, but I'd like to suggest that you (1) use re.VERBOSE to write a regexp someone can understand later; (2) compile the regexp to reduce clutter at the call site; and, (3) tighten some of the matching criteria. Like so:

def conv(m):
    return chr(int(m.group(1)))

pat = re.compile(r"""[+\s]*    # optional whitespace or +
                     \b        # word boundary
                     n?char    # NCHAR or CHAR
                     \(        # left paren
                     ([\d\s]+) # digits or spaces - group 1
                     \)        # right paren
                     [+\s]*    # optional whitespace or +
                  """, re.VERBOSE | re.IGNORECASE)
print pat.sub(conv, data)

Note that I changed your str to data : str is the name of a heavily used builtin function, and it's a Really Bad Idea to create a variable with the same name.

Answer 3

You only need to use a word boundary \\b :

def conv(m):
    return chr(int(m.group(1)))

print re.sub(r'\bn?char\(([^)]+)\)(?:\s*\+\s*)?', conv, str, re.IGNORECASE)