[英]Select one specfic row from each user by a different time
I want to select the last answer for a specific question. 我想为特定问题选择最后一个答案。 My current solution selects only the Question from "Nutzer1237", but i want the last Answer from "Nutzer1234" too.
我当前的解决方案仅从“ Nutzer1237”中选择问题,但我也希望从“ Nutzer1234”中获得最后一个答案。
SELECT pid, frage, antwort, user, created_at
FROM antwortenverlauf
WHERE frage = 'Risiko: Wie empfinden Sie die Kommunikation mit dem Kunden?'
AND (
user, created_at
)
IN (
SELECT user, MAX( created_at )
FROM antwortenverlauf
)
ORDER BY created_at DESC
Sorry for my English! 对不起我的英语不好!
Translation: frage = question 翻译:frage =问题
antwort = answer antwort =答案
In the official manual there are 3 examples how to solve this. 在官方手册中 ,有3个如何解决此问题的示例。
Task: For each article, find the dealer or dealers with the most expensive price.
任务:对于每件商品,找到价格最昂贵的经销商 。
This problem can be solved with a subquery like this one:
这个问题可以通过像这样的子查询来解决:
SELECT article, dealer, price
FROM shop s1
WHERE price=(SELECT MAX(s2.price)
FROM shop s2
WHERE s1.article = s2.article);
The preceding example uses a correlated subquery, which can be inefficient (see Section 13.2.10.7, “Correlated Subqueries”).
前面的示例使用了一个关联子查询,该子查询可能效率不高(请参见第13.2.10.7节“关联子查询”)。 Other possibilities for solving the problem are to use an uncorrelated subquery in the FROM clause or a LEFT JOIN.
解决该问题的其他可能性是在FROM子句或LEFT JOIN中使用不相关的子查询。
Uncorrelated subquery:
不相关的子查询:
SELECT s1.article, dealer, s1.price
FROM shop s1
JOIN (
SELECT article, MAX(price) AS price
FROM shop
GROUP BY article) AS s2
ON s1.article = s2.article AND s1.price = s2.price;
LEFT JOIN:
左联接:
SELECT s1.article, s1.dealer, s1.price
FROM shop s1
LEFT JOIN shop s2 ON s1.article = s2.article AND s1.price < s2.price
WHERE s2.article IS NULL;
The LEFT JOIN works on the basis that when s1.price is at its maximum value, there is no s2.price with a greater value and the s2 rows values will be NULL.
LEFT JOIN的工作原理是,当s1.price达到最大值时,不存在更大的s2.price且s2行的值将为NULL。
Your query works as expected giving the record with Nutzer1237
as 'user', because, in your subquery, you're looking for the records with the most recent timestamp: MAX( created_at )
without grouping your results per user
. 您的查询按预期方式工作,以
Nutzer1237
作为“用户”给出记录,因为在子查询中,您正在查找具有最近时间戳记的记录: MAX( created_at )
而不将每个user
的结果分组。
You have then to group the results per user
in your subquery, using this query: 然后,您必须使用以下查询在子查询中将每个
user
的结果分组:
SELECT user, MAX( created_at )
FROM antwortenverlauf
GROUP BY user
Note: Make sure also that the value of the frage
column you're looking for doesn't contain undesired spaces or other characters. 注意:还请确保您要查找的
frage
列的值不包含不希望的空格或其他字符。
However, your query won't get your desired results because you're looking for the MAX(created_at)
without considering the frage
column. 但是,您的查询不会得到您想要的结果,因为您在查找
MAX(created_at)
未考虑frage
列。 You have to move the WHERE
condition in your subquery. 您必须在子查询中移动
WHERE
条件。 Your final query will then look like this: 您的最终查询将如下所示:
SELECT pid, frage, antwort, user, created_at
FROM antwortenverlauf
WHERE (user, created_at)
IN (
SELECT user, MAX( created_at )
FROM antwortenverlauf
WHERE frage = 'Risiko: Wie empfinden Sie die Kommunikation mit dem Kunden?'
GROUP BY user
)
ORDER BY created_at DESC
you should have read the answer of @fancyPants 您应该已经阅读@fancyPants的答案
SELECT pid, frage, antwort, user, created_at
FROM antwortenverlauf a1
WHERE frage = 'Risiko: Wie empfinden Sie die Kommunikation mit dem Kunden?'
AND (user, created_at) IN (SELECT user, MAX( created_at )
FROM antwortenverlauf a2
WHERE a1.frage=a2.frage
GROUP BY USER)
ORDER BY created_at DESC
SELECT pid, frage, antwort, user, created_at
FROM antwortenverlauf
WHERE frage = 'Risiko: Wie empfinden Sie die Kommunikation mit dem Kunden?'
AND (
user, created_at
)
IN (
SELECT user, MAX( created_at )
FROM antwortenverlauf
GROUP BY USER // **this is the only difference**
)
ORDER BY created_at DESC
in your code the inner query only return one raw that was the problem 在您的代码中,内部查询仅返回一个原始问题
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.