将参数传递给Java线程

Question

I seen already : How can I pass a parameter to a Java Thread?

But I don't know how exactly use that. So I made easy samle code to save your precious time :

class ThreadParam implements Runnable { 
static int c;

public ThreadParam(int a, int b){
    int c = a+b;
}

public void run(){
    System.out.println(c);
}

}

public class ThreadParamTest {
public static void main(String args[]){
    Runnable r = new ThreadParam(1000,2000);
    new Thread(r).start();  
}   
}

Why is this result 0 ? I think that should be 3000. Maybe the variable "int c" isn't dispatch to run() method. How can I solve this issue?

Answer 1

I think the choice of "static int c" is incorrect as it means that all instances of ThreadParam will "share" (and poorly at that) a common value for c. That is to stay, if you have 2 separate ThreadParams going simultaneously, one of them is likely present the "wrong" value for C. Consider...

class BadThreadParam implements Runnable {
    static int c;

    public BadThreadParam( int a, int b ) {
        c = a + b;
    }

    public void run() {
        System.out.println( c );
    }
}

class ImmutableThreadParam implements Runnable {
    private final int c;

    public ImmutableThreadParam( int a, int b ) {
        c = a + b;
    }

    public void run() {
        System.out.println( c );
    }
}

public class BadThreadParamTest  {
    public static void main( String[] args ) {
        BadThreadParam shouldBe3 = new BadThreadParam( 1, 2 );
        BadThreadParam shouldBe5 = new BadThreadParam( 3, 2 );
        shouldBe3.run();  // Expect 3 but is 5.  WTF?
        shouldBe5.run();  // Expect 5.

        ImmutableThreadParam expect3 = new ImmutableThreadParam( 1, 2 );
        ImmutableThreadParam expect5 = new ImmutableThreadParam( 3, 2 );
        expect3.run();  // Expect 3.
        expect5.run();  // Expect 5.
    }
}

If you make the "c" local to the instance, you overcome the "2 separate ThreadParams are affecting the same value" problem. If you make the "private int c" final, you are avoiding the need for synchronization. If you need to mutate "c" down in the run (or from the outside), now you are entering the world of synchronization...

class ThreadSafeMutableThreadParam implements Runnable {
    private int c;

    public ThreadSafeMutableThreadParam( int a, int b ) {
        c = a + b;
    }

    public synchronized void setC( int c ) {
        this.c = c;
    }

    public synchronized int getC() {
        return c;
    }

    public void run() {
        System.out.println( getC() );
    }
}

Other than that, tuxdna's is correct in describing how you "pass params to a Runnable". The Runnable is inconsequential; you are passing params to a class (however you achieve that). If you need them available down in a run(), you need to be aware of synchronization.

Answer 2

The result is 0 because in constructor you're not actually assigning new value to static int c , but you're assigning it to local variable c .

Change int c into c in constructor.

Answer 3

c should not be static and should be assigned in your constructor. In your example, you've assigned to a variable c , not the field.

Here is the corrected code:

class ThreadParam implements Runnable { 
private int c;

public ThreadParam(int a, int b){
    this.c = a+b;
}

public void run(){
    System.out.println(c);
}

}

Answer 4

Your 'c' variable is defined twice: once at the class level (with a static modifier) and once in the ThreadParam constructor. Remove the 'static' on the class field and remove the 'int' inside the constructor.

Answer 5

Runnable is only an interface that requires you to define a run() method, nothing more nor less. So, essentially, you are free to declare your class constructor any way you want ( you are passing two integers a and b ) to be able to access them from run() method.

Also you are defining a local variable in the constructor that is destroyed after the constructor has finished. Which leaves your static int c value to be still 0 .

Here is the fixed version:

class ThreadParam implements Runnable {
    private int c;

    public ThreadParam(int a, int b) {
        c = a + b;
    }

    public void run() {
        System.out.println(c);
    }

}

public class ThreadParamTest {

    public static void main(String args[]) {
        Runnable r = new ThreadParam(1000, 20000);
        new Thread(r).start();
    }
}

And the output is 21000 ( and not 3000 )