使用fetch_object（）从MySQL显示另一个相关表中的行

Question

Trying to echo the author column from a another table. Currently have two tables in database one is called entries and the other comments . Both have IDs but both have the same column name "author". In the SQL statement you would do select * from $table1 t1, $table2 t2 where t1.blogID = t2.blogID and t1.blogID = $postID . I know how to echo from just one table using fetch_object()

if (!empty($postID)) {
$command = "select * from $table_name where blogID = $postID";
$result = $db->query($command);
while ($data = $result->fetch_object()) {
  $postID = $data->blogID;
  echo "<TR><TD>".$postID."</TD>";
  echo "<TD>".$data->author."</TD>";
  echo "<TD>".$data->date."</TD>";
  echo "<TD>".$data->entry."</TD></TR>\n";

But, then, if I want the $command to select on both tables, how would I echo let say t1.author ? Meaning do I do $data->t1.author ? Does that make sense? Or what do you guys suggest using the format I've set-up above?

Answer 1

$command="select t1.name as t1name , t2.name as t2name from t1tabla as t1 ,t2table as t2";
$result = $db->query($command);
while ($data = $result->fetch_object()) {

 echo $data->t1name .'<br>';
 echo $data->t2name.'<br>' 
}