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初始化多维列表后,Python列表分配超出范围

[英]Python list assignment out of range after initializing multidimensional list

So, I'm trying to work with multidimensional lists to make a map for an ASCII game. 所以,我正在尝试使用多维列表来制作ASCII游戏的地图。 I have code to initialize the list, 我有代码来初始化列表,

mapData = [[[0 for m in range(3)] for x in range(32)] for y in range(32)] 

then I try to access and change a value in the variable using this code, 然后我尝试使用此代码访问和更改变量中的值,

mapData[0][5][5] = 1

and get this error message, 并收到此错误消息,

IndexError: list assignment index out of range

I've tried many things, but can't figure anything out. 我尝试了很多东西,但无法解决任何问题。

Your innermost list has only three cells, so trying to access [5] on it won't work. 你最里面的列表只有三个单元格,所以试图访问它[5]是行不通的。

The indices go from outermost (with 32 entries) to innermost (with 3 entries). 索引从最外层(有32个条目)到最里面(有3个条目)。 If you expected your innermost list to have 6 or more cells, you need to adjust your for m in range(3) loop. 如果您希望最里面的列表包含6个或更多单元格,则需要for m in range(3)循环中调整for m in range(3)

If you expected to index the first cell of the innermost list, perhaps you needed to reverse the indices: 如果您希望索引最里面列表的第一个单元格,也许您需要反转索引:

mapData[5][5][0] = 1

To spell it out some more: 再解释一下:

  • mapData[0] returns the first element of the outermost list, generated by the for y in range(32) loop in your nested list comprehensions. mapData[0]返回最外层列表的第一个元素,由嵌套列表mapData[0]for y in range(32)循环生成。
  • [5] in mapData[0][5] then accesses the 6th element of the previous result, a list from the for x in range(32) loop. [5]mapData[0][5]然后访问先前结果的第六元件,从所述列表for x in range(32)循环。
  • [5] in mapData[0][5][5] tries to index the innermost list, one of the list objects generated by [0 for m in range(3)] . [5]mapData[0][5][5]试图索引的最内列表中,所产生的列表中的对象中的一个[0 for m in range(3)] Because those lists only have 3 0 values each, an IndexError exception is raised. 因为这些列表每个只有3 0值,所以会引发IndexError异常。

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