简体   繁体   English

使用INNER JOIN从两个表中删除数据

[英]Delete data from two tables with INNER JOIN

I want to delete data from two tables with one SQL query according to datetime_lastactive and if the IP addresses is matching your own. 我想根据datetime_lastactive使用IP查询从两个表中删除数据,并且IP地址是否与您自己的数据匹配。 But I'm getting this error message when I try out the following SQL query: 但是,当我尝试以下SQL查询时,我收到此错误消息:

Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INNER JOIN visitors_main WHERE information_ipaddress = '123.123.123.123' A' at line 2' in ...

DELETE FROM visitors_list
INNER JOIN visitors_main
WHERE information_ipaddress = :ipaddress
AND datetime_lastactive < NOW() - INTERVAL 3 HOUR

The tables looks like this: 这些表如下所示:

CREATE TABLE IF NOT EXISTS `visitors_list` (
  `id` int(10) NOT NULL AUTO_INCREMENT,
  `id_visitor` int(10) DEFAULT '0',
  `id_user` int(10) DEFAULT '0',
  `data_filename` text NOT NULL,
  `data_filename_get` text NOT NULL,
  `data_useragent` text NOT NULL,
  `datetime_lastactive` datetime NOT NULL,
  `information_ipaddress` text NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `id` (`id`)
)

CREATE TABLE IF NOT EXISTS `visitors_main` (
  `id` int(10) NOT NULL AUTO_INCREMENT,
  `id_user` int(10) DEFAULT '0',
  `data_coordinates` varchar(25) NOT NULL,
  `datetime_firstvisit` datetime NOT NULL,
  `checkbox_anonymous` tinyint(4) DEFAULT '0',
  `checkbox_tiecoordinates` tinyint(4) DEFAULT '0',
  `checkbox_nogps` tinyint(4) DEFAULT '0',
  `information_ipaddress` text NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `id` (`id`)
)

How can I make this work? 我该如何进行这项工作?

Try this instead: 尝试以下方法:

DELETE l, m
FROM visitors_list AS l
INNER JOIN visitors_main AS m ON l.information_ipaddress = m.information_ipaddress
WHERE l.information_ipaddress = :ipaddress
AND l.datetime_lastactive < NOW() - INTERVAL 3 HOUR;
DELETE v1,v2
FROM visitors_list v1
INNER JOIN visitors_main v2 ON v1.id_visitor = v2.id
WHERE v1.information_ipaddress = :ipaddress
AND v1.datetime_lastactive < NOW() - INTERVAL 3 HOUR;

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM