jQuery cookie-如何使用cookie

Question

I need to post ID value from page with jeasyui Grid, to another demo.php,for creating pdf report. So my idea was to use cookies, like this.

  $(function () {

        $("#btnCookie").bind("click", function () {
        var row = $('#tt').datagrid('getSelected');
    if (row){
            $.cookie("name",row.id);
          alert($.cookie("id"));//just to check for value ,and it is OK!
            window.location.href = "demo.php";
        }});
    });

after submit,I get right value. On demo.php I use this to get cookies value:

         $(function () {
        if ($.cookie("id") != null ) {
           var id = $.cookie("name");

            $.removeCookie("id");
           }
    });
</script>

now my problem is to put cookie values in next query in php section:

$result = mysqli_query($con,"SELECT * FROM stan where id="HERE I need cookie value"

Answer 1

What you're looking for is:

$_COOKIE["something"] 

I hope you find out the rest :) (Make sure you use proper quotes in your string, not like you wrote it in the question; also be aware of the syntax of implanting array element refs into strings; finally, watch out for cookie value, it can be manipulated so protect your query against tricky values.)

Answer 2

You're setting jQuery cookie correctly. To call it and search your database just use it in the query like so:

<?  
    $value = $_POST['rowValue'];

    $stmt = $con->prepare("
        SELECT * 
        FROM stan 
        WHERE id = ?
    ");

    $stmt->execute(array($value));

    $result = $stmt->fetchAll(PDO::FETCH_ASSOC);   
?>

EDIT: Updated because of comment:

<script>
$.post("demo.php", {
        rowValue: row.id //The cookie value
    }
});
</script>

So I now understand that you want to pass the cookie value, not the cookie name to your php file. For this you don't need to set a cookie, you can just send the value to the php file. In my example I've used the jQuery ajax post function. I've updated my example PHP accordingly.